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Re: Rules 1. Time yourself 2. Work your solution on a seperate [#permalink]
I will go for A (only statement 1 can be used to answer).
Time taken 30 seconds.

Sol. Three integers be X,Y,Z and largest be Z.
sqrt(XYZ) = Z ,replace Z by 12
sqrt(XY*12) = 12
or sqrt(XY) = sqrt(12)
or XY = 12
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Re: Rules 1. Time yourself 2. Work your solution on a seperate [#permalink]
Agree with mantha and mdfrahim, think that the answer is A)
Time: 2,5 min.
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Re: Rules 1. Time yourself 2. Work your solution on a seperate [#permalink]
a) sqrt( a * b * 12 ) = 12
so a * b = 12
Sufficient
b) a+b+c = 20
Only number that satisfies this and a * b = c is c = 12
Sufficient
< 2 minutes
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Re: Rules 1. Time yourself 2. Work your solution on a seperate [#permalink]
praetorian123 wrote:
Rules

1. Time yourself
2. Work your solution on a seperate sheet of paper
3. write your solution here , and your time please.

If the square root of the product of three distinct positive
integers is equal to the largest of the three numbers, what is the
product of the two smaller numbers?

(1) The largest number is 12.
(2) The average (arithmetic mean) of the three numbers is 20/3



D is correct

good work anand :)
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Re: Rules 1. Time yourself 2. Work your solution on a seperate [#permalink]
I agree with Anandnk and Kpadma.

D is the answer.

The only distinct positive integers that satisfy the requirement that their sum = 20, and that the largest integer = the product of the other 2 integers are 6, 2 and 12.

If you try other combinations, you'll find that they don't sum to 20. Example: a=3; b=4 ; ab = c = 12 but 3 + 4 + 12 20. Same with 8, 2 and 16.



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