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Cubiod with x,y,z as Length, Breadth and Height. What is the

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mba
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Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   15 Mar 2004, 08:00
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Cubiod with x,y,z as Length, Breadth and Height. What is the volume:

1) x = 1200/yz
2) Celing Surface area is 120 and Surface area of each of facing wall is 100.

Answers with explanation please!



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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   15 Mar 2004, 08:23
A)


Volume = xyz
1) x = 1200/yz => xyz=1200 - Sufficient

2) Celing Surface area is 120 and Surface area of each of facing wall is 100.

We just know, xy=120 and yz=100. - Insufficient
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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   15 Mar 2004, 09:29
I second Geethu's explanation.

A is the answer.
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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   15 Mar 2004, 12:18
area 1 = 120 = 12 * 10
area 2 = 100 = 10 * 10
So volume = 12 * 10 * 10 = 1200

Now

area 1 = 120 = 40 * 3
area 2 = 100 = 40 * 2.5

Volume = 40 * 3 * 2.5 = 300

So we cannot tell what the volume is from B
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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   15 Mar 2004, 18:01
mba wrote:

2) Celing Surface area is 120 and Surface area of each of facing wall is 100.



Length = L
Width = W
Height = H

Celing Surface Area = L * W = 120
surface area of each of facing wall = L * H = W * H = 100
(All the side faces are having the same surface area)

L * W * H^2 = 10000
H = SQRT(10000/120)

Volume = L * W * H = 120 * SQRT(10000/120)

Thus, Answer is D

What am I doing wrong?
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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   15 Mar 2004, 23:40
Its definitely NOT D
L*W=120
W*H=100

L & W could be 10 & 12, 2 & 60, and so on, if which case H can be a number ((lol:) a number, plural) :roll: of heights. In other words

10*12=120
10*10=100

Area 10*10*12=1200

If:
2*60=120
2*50=100

Area 2*50*60=6000

Any thoughts?
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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   16 Mar 2004, 01:22
Well guess what! the correct answer is (A).

But still I am confused at the explanation given by Kaplan.
As per Kaplan:
1) Sufficient.

2) if x,y,z is length, breadth and Height. Then xy=120, yz=100 and xz=100 (As surface of [b]EACH of the facing side is given[\b] . Hence it is not sufficient to get the volume.(This is what Kaplan says)

But what I feel is if xy=120, yz=100, xz=100. Then (xyz)^2 = 120*100*100
As volume cannot be negative hence, (2) is also sufficient to find the volume.

To my understanding (D) should be the answer but as per Kaplan (A) is the answer. (Sometime books can also be wrong!)

Any comments!
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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   16 Mar 2004, 17:44
Hey MBA,

I agree

I wasnt sure initially what they ment my cubiod. Now, if in fact, that means a cube where two of the three sides must equal, then the answer MUST BE D.

In a cube xy=120 =>> x=y =>> x^2=120 ===> x or y =Sqrt(120)=~11

from the second statement we have x which is sqr(120)*z=100, ==>
z~=9.1 There is only one possible value for Z

Conclusion we know that x=y, therefore Volume is 120*9.1=1092

The are no two possible answers, therefore statement (2) is enough.

Any ideas?
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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink] New post   16 Mar 2004, 20:03
lvb9th wrote:
I wasnt sure initially what they ment my cubiod. Now, if in fact, that means a cube where two of the three sides must equal, then the answer MUST BE D.


A cube is a special case of cuboid.



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Re: Cubiod with x,y,z as Length, Breadth and Height. What is the [#permalink]
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