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OK, first post but (as all say) I have been reading for a

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3underscore
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OK, first post but (as all say) I have been reading for a [#permalink] New post   07 Jan 2007, 15:01
OK, first post but (as all say) I have been reading for a while and it has been a valuable resource. Well, also slightly intimidating, as everyone seems to have committed a lot more prep time to the GMAT than I could manage.

Anyway, I have the test tomorrow, and on the practice test only got one question that I cannot resolve. It was the first one, I got it wrong, and I can't work out the underlying process to get the answer (all the others made fair sense).

Anyway

5^21 * 4^11 = 2 * 10^n

Find n. The answers available don't really matter, I would just really appreciate a full solution so I can see what rules I am missing.



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Re: OK, first post but (as all say) I have been reading for a [#permalink] New post   07 Jan 2007, 15:13
4^11 = (2^2)^11 = 2^22 = 2 * 2^21

5^21 * 2 * 2^21 = 2 * (5 * 2)^21 = 2 * 10^21

n = 21

peanuts ;)
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3underscore
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Re: OK, first post but (as all say) I have been reading for a [#permalink] New post   07 Jan 2007, 15:34
Thank you very much. I remember being poor at deconstructing exponentials about 12 years ago as well!

Makes good sense now - I will go back to swotting on my exponential rules.
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Re: OK, first post but (as all say) I have been reading for a [#permalink] New post   07 Jan 2007, 17:51
braindancer wrote:
Never argue with an idiot. They drag you down to their level, then beat you with experience.


Very touchy. I like it.

But should not it be like this "Never argue with idiots. They drag you down to their level, then beat you with their experience."?
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Re: OK, first post but (as all say) I have been reading for a [#permalink] New post   08 Jan 2007, 02:53
Well yes, I think you're right, but it's a quote so I left it that way :)

Don't overGMAT on everything - sometimes sentence correction is not really necessary :lol:
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Re: OK, first post but (as all say) I have been reading for a [#permalink] New post   10 Jan 2007, 09:10
5^21*2^22=2*2^n*5^n
5^21*2^22=2^(n+1)5^n
n+1=22 n=21



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Re: OK, first post but (as all say) I have been reading for a [#permalink]
10 Jan 2007, 09:10
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