Bunuel
In a sequence of numbers in which each term after the first term is 1 more than twice the preceding term, what is the fifth term?
(1) The first term is 1.
(2) The sixth term minus the fifth term is 32.
DS21222
Given: In a sequence of numbers in which each term after the first term is 1 more than twice the preceding term Let's take a moment to see what this pattern looks like.
Let k = the term_1
So, we get:
term_1 = k
term_2 = 2k + 1
term_3 = 2(k + 1) + 1 = 2k + 3
term_4 = 2(2k + 3) + 1 = 4k + 7
term_5 = 2(4k + 7) + 1 = 8k + 15
term_6 = 2(8k + 15) + 1 = 16k + 31
So,
term_5 = 8k + 15Target question: What is term_5? Statement 1: The first term is 1. In other words, k = 1
Since we already determined that
term_5 = 8k + 15, we can substitute to get:
term_5 = 8(1) + 15 = 16 + 15 = 31Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: The sixth term minus the fifth term is 32From our pattern we can see that
term_5 = 8k + 15 and
term_6 = 16k + 31So, statement 2 is telling us that (
16k + 31) - (
8k + 15) = 32
Simplify the left side to get: 8k + 16 = 32
At this point, we can see that we COULD solve the equation for k, which means we COULD determine the value of term_5 the same way we did for statement 1 (although we would never waste valuable time on test day doing so)
Since we COULD answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: D
Cheers,
Brent