What is the value of the integer n? (1) n^2+ 3n = 4 (2) (n + 3)^n = 1

ChanSu - Can you please elaborate on the reasoning?

IMO, If n = 1, Statement 2 gets violated

\((1+3)^1 \neq 1\)

Let me know if I am missing anything.

Sry . My bad . N=-4 is correct

But your statement 2 should written as (-4+3) ^-4 = 1 which translates to n=-4

n = -4 is a valid value for Statement 2, so is n = -2 and n = 0.

In DS question, each statement needs to be evaluated in isolation. It is not necessary to find out / conclude all possible values that a variable can hold in a particular statement. For ex. In this question, the moment we conclude that n can have multiple values in Statment 2, we can reject that statement and move to the subsequent step. One may take n = -4 as a possible value in Statement 2 to conclude insufficiency, which is perfectly fine, but it's not necessary to do so.

Only when the statements are combined, any additional values from Statement 1 can be evaluated in light of Statement 2 (or vice versa).

Got it. But n=-4 needs to be considered in this case because when you combine statements 1 and 2 (after you’re done evaluating statement 2) , n=-4 will be common to both

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