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Re: Of the people who donated money to a certain local theater last year [#permalink]
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gmatophobia wrote:
Bunuel wrote:
Of the people who donated money to a certain local theater last year, 1/4 donated $20 or less and 2/3 donated more than $20 but less than $1,000. If the average (arithmetic mean) amount donated by the people who donated more than $20 but less than $1,000 was $180, what was the average amount donated by the people who donated $1,000 or more?

(1) The average amount donated by the people who donated less than $1,000 was $132.
(2) The average amount donated by the people who donated more than $20 was $360.

Attachment:
2023-08-15_11-00-18.png


We have three categories of donors

1) Who donated $20 or less - We will refer to this category as Group 1
2) Who donated more than $20 but less than $1,000 - We will refer to this category as Group 2
2) Who donated more than $1,000 - We will refer to this category as Group 3

Assume that the total number of donors is \(12x\) (LCM of 3x and 4x).

Number of people in each group

  • Group 1: \(\frac{1}{4} * 12x = 3x\)
  • Group 2: \(\frac{2}{3} * 12x = 8x\)
  • Group 3: \(12x - 11x = x\)

...If the average (arithmetic mean) amount donated by the people who donated more than $20 but less than $1,000 was $180...

Amount Donated

  • Group 1: \(p\)
  • Group 2: \(180*3x\)
  • Group 3: \(q\)

Question:\( \frac{q}{x}\) ?

Statement 1

(1) The average amount donated by the people who donated less than $1,000 was $132.

\(\frac{180*3x + p }{ 11x}= 132\)

We don't have any information given in the premise or in this stem to calculate \(q\). Hence, the statement alone is not sufficient. We can eliminate A and D.

Statement 2

(2) The average amount donated by the people who donated more than $20 was $360.

\(\frac{180*3x + q }{ 17x }= 360\)

\(180*3x + q = 360 * 17x\)

\(q = 360 * 17x - 180 * 3x\)

\(q = x(360 * 17 - 180 * 3)\)

\(\frac{q}{x} = (360 * 17 - 180 * 3)\)

We have a definite answer. Hence, this statement alone is sufficient.

Option B


Why is Group 2 180*3x instead of 180*8x?
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Re: Of the people who donated money to a certain local theater last year [#permalink]
In the 2nd solution, wouldnt we divide it by 9x?





gmatophobia wrote:
Bunuel wrote:
Of the people who donated money to a certain local theater last year, 1/4 donated $20 or less and 2/3 donated more than $20 but less than $1,000. If the average (arithmetic mean) amount donated by the people who donated more than $20 but less than $1,000 was $180, what was the average amount donated by the people who donated $1,000 or more?

(1) The average amount donated by the people who donated less than $1,000 was $132.
(2) The average amount donated by the people who donated more than $20 was $360.

Attachment:
2023-08-15_11-00-18.png


We have three categories of donors

1) Who donated $20 or less - We will refer to this category as Group 1
2) Who donated more than $20 but less than $1,000 - We will refer to this category as Group 2
2) Who donated more than $1,000 - We will refer to this category as Group 3

Assume that the total number of donors is \(12x\) (LCM of 3x and 4x).

Number of people in each group

  • Group 1: \(\frac{1}{4} * 12x = 3x\)
  • Group 2: \(\frac{2}{3} * 12x = 8x\)
  • Group 3: \(12x - 11x = x\)

...If the average (arithmetic mean) amount donated by the people who donated more than $20 but less than $1,000 was $180...

Amount Donated

  • Group 1: \(p\)
  • Group 2: \(180*3x\)
  • Group 3: \(q\)

Question:\( \frac{q}{x}\) ?

Statement 1

(1) The average amount donated by the people who donated less than $1,000 was $132.

\(\frac{180*3x + p }{ 11x}= 132\)

We don't have any information given in the premise or in this stem to calculate \(q\). Hence, the statement alone is not sufficient. We can eliminate A and D.

Statement 2

(2) The average amount donated by the people who donated more than $20 was $360.

\(\frac{180*3x + q }{ 17x }= 360\)

\(180*3x + q = 360 * 17x\)

\(q = 360 * 17x - 180 * 3x\)

\(q = x(360 * 17 - 180 * 3)\)

\(\frac{q}{x} = (360 * 17 - 180 * 3)\)

We have a definite answer. Hence, this statement alone is sufficient.

Option B
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Re: Of the people who donated money to a certain local theater last year [#permalink]
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Yes. I believe it'll look like this

\(\frac{180*8x + q }{ 9x }= 360\)

\(180*8x + q = 360 * 9x\)

\(q = 360 * 9x - 180 * 9x\)

\(q = x(360 * 9 - 180 * 3)\)

\(\frac{q}{x} = 1800\)
Dhruv1212 wrote:
In the 2nd solution, wouldnt we divide it by 9x?





gmatophobia wrote:
Bunuel wrote:
Of the people who donated money to a certain local theater last year, 1/4 donated $20 or less and 2/3 donated more than $20 but less than $1,000. If the average (arithmetic mean) amount donated by the people who donated more than $20 but less than $1,000 was $180, what was the average amount donated by the people who donated $1,000 or more?

(1) The average amount donated by the people who donated less than $1,000 was $132.
(2) The average amount donated by the people who donated more than $20 was $360.

Attachment:
2023-08-15_11-00-18.png


We have three categories of donors

1) Who donated $20 or less - We will refer to this category as Group 1
2) Who donated more than $20 but less than $1,000 - We will refer to this category as Group 2
2) Who donated more than $1,000 - We will refer to this category as Group 3

Assume that the total number of donors is \(12x\) (LCM of 3x and 4x).

Number of people in each group

  • Group 1: \(\frac{1}{4} * 12x = 3x\)
  • Group 2: \(\frac{2}{3} * 12x = 8x\)
  • Group 3: \(12x - 11x = x\)

...If the average (arithmetic mean) amount donated by the people who donated more than $20 but less than $1,000 was $180...

Amount Donated

  • Group 1: \(p\)
  • Group 2: \(180*3x\)
  • Group 3: \(q\)

Question:\( \frac{q}{x}\) ?

Statement 1

(1) The average amount donated by the people who donated less than $1,000 was $132.

\(\frac{180*3x + p }{ 11x}= 132\)

We don't have any information given in the premise or in this stem to calculate \(q\). Hence, the statement alone is not sufficient. We can eliminate A and D.

Statement 2

(2) The average amount donated by the people who donated more than $20 was $360.

\(\frac{180*3x + q }{ 17x }= 360\)

\(180*3x + q = 360 * 17x\)

\(q = 360 * 17x - 180 * 3x\)

\(q = x(360 * 17 - 180 * 3)\)

\(\frac{q}{x} = (360 * 17 - 180 * 3)\)

We have a definite answer. Hence, this statement alone is sufficient.

Option B




 

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Re: Of the people who donated money to a certain local theater last year [#permalink]
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­Hi all,
I found a simpler way to solve the question than the ways shared in this post.

Imagine just drawing a BAR Graph with the 3 Groups
1) people who donated 20 or less --> 1/4 or 3/12 of the total donors
2) people who donated more than 20 and less than $1000 --> 2/3 or 8/12 of the total donors            - AVG MEAN of this donatios $180
3) people who donated more than $1000 --> 1/12 of the total donors (1 - the previous values)

Notice that for this excersie we can set a proportion of 3 : 8 : 1 respectively for the donors groups.

Statement #1
They give us just information about Group 1 and Group 2. There is no possible way to estimate how much Group 3 donated.
So discarded, but note that we could get the average of group 1 if needed.

Eliminate answers: A & D

Statement #2
They give us information about the Group 2 and Group 3! Bingo!
So $360 is the average for 9 donors -> Total donations: $3240 form Group 2 & 3.
If we estimate the total Donations for just group 2 (it would be $180 x 8 --> $1440)
So Group 3 is the difference of this values, beign $1800 for just 1 donor.

So statement 2 is correct

Answer B


 
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