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Re: A certain portfolio consisted of 5 stocks, priced at $20, [#permalink]
1. Find what is 2% increase in $ for an average stock (for all stocks).

2. (20+35+40+45+70)*0.02 = 4.2$

3. Now we get the greatest diff when there is 15% increase on 70 and 35% decrease on 20 which is 10.5 - 7 = 3.5. For all other options it will be less then 3.5.

Therefore I agree with E
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Re: A certain portfolio consisted of 5 stocks, priced at $20, [#permalink]
KillerSquirrel wrote:
1. Find what is 2% increase in $ for an average stock (for all stocks).

2. (20+35+40+45+70)*0.02 = 4.2$

3. You know that to yield 4.2$ for all five stocks one stock rose 0.15 and one fell 0.35.

4. 0.15x-0.35y = 4.2 ---> 0.05(3x-7y) = 4.2 ---> 3x-7y = 84

5. The only two stocks that can give you the closest solution for x,y are 70 and 20.

the answer is (E)


KS: Here's where I'm having trouble. The stem states that 'the average price of a stock in the portfolio rose by approximately 2%'. So why are you multiplying the sum (210) by .02 and not the average (210/5=42) by .02?

Thanks.
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Re: A certain portfolio consisted of 5 stocks, priced at $20, [#permalink]
GK_Gmat wrote:
KillerSquirrel wrote:
1. Find what is 2% increase in $ for an average stock (for all stocks).

2. (20+35+40+45+70)*0.02 = 4.2$

3. You know that to yield 4.2$ for all five stocks one stock rose 0.15 and one fell 0.35.

4. 0.15x-0.35y = 4.2 ---> 0.05(3x-7y) = 4.2 ---> 3x-7y = 84

5. The only two stocks that can give you the closest solution for x,y are 70 and 20.

the answer is (E)


KS: Here's where I'm having trouble. The stem states that 'the average price of a stock in the portfolio rose by approximately 2%'. So why are you multiplying the sum (210) by .02 and not the average (210/5=42) by .02?

Thanks.




let me handle this KS:

The orignal average comes out to be 42 as u know.
Now 2% of 42 = 0.84
So the total average is now 42.84
When we multiply the average (42.84) by 5 we get 214.2
which is 4.2 more then the orignal total (210)
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Re: A certain portfolio consisted of 5 stocks, priced at $20, [#permalink]
GK_Gmat wrote:
KillerSquirrel wrote:
1. Find what is 2% increase in $ for an average stock (for all stocks).

2. (20+35+40+45+70)*0.02 = 4.2$

3. You know that to yield 4.2$ for all five stocks one stock rose 0.15 and one fell 0.35.

4. 0.15x-0.35y = 4.2 ---> 0.05(3x-7y) = 4.2 ---> 3x-7y = 84

5. The only two stocks that can give you the closest solution for x,y are 70 and 20.

the answer is (E)


KS: Here's where I'm having trouble. The stem states that 'the average price of a stock in the portfolio rose by approximately 2%'. So why are you multiplying the sum (210) by .02 and not the average (210/5=42) by .02?

Thanks.


It's the same thing, but its easier to work with the sum rather then the average.

assume three stocks (10, 20, 30) ---> 30 decreased by 50%

sum = 60 ---> average = 20 ---> 2% sum = 0.12 ---> 2% average = 0.04 (i.e. 0.12/3)

after 50% decrease

sum = 45 ---> average = 15 ---> 2% sum = 0.09 ---> 2% average = 0.03 (0.09/3)

:)
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Re: A certain portfolio consisted of 5 stocks, priced at $20, [#permalink]
sportyrizwan wrote:
GK_Gmat wrote:
KillerSquirrel wrote:
1. Find what is 2% increase in $ for an average stock (for all stocks).

2. (20+35+40+45+70)*0.02 = 4.2$

3. You know that to yield 4.2$ for all five stocks one stock rose 0.15 and one fell 0.35.

4. 0.15x-0.35y = 4.2 ---> 0.05(3x-7y) = 4.2 ---> 3x-7y = 84

5. The only two stocks that can give you the closest solution for x,y are 70 and 20.

the answer is (E)


KS: Here's where I'm having trouble. The stem states that 'the average price of a stock in the portfolio rose by approximately 2%'. So why are you multiplying the sum (210) by .02 and not the average (210/5=42) by .02?

Thanks.




let me handle this KS:

The orignal average comes out to be 42 as u know.
Now 2% of 42 = 0.84
So the total average is now 42.84
When we multiply the average (42.84) by 5 we get 214.2
which is 4.2 more then the orignal total (210)


Thanks - I'm just not as fast :wink:
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Re: A certain portfolio consisted of 5 stocks, priced at $20, [#permalink]
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