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Re: 1:if x and 10 are relatively prime natural numbers, then x [#permalink]
My question to ssandeepan:

If what you say is true...and X and 10 have no similar prime factors, then how can the answer be 9?
The question asks which # can X be a multiple of. If X is a multiple of 9, then it can be 9 and then the disimilar factorization holds true but what if X is 18 (a multiple of 9)..then 18 and 10 have 2 as a common prime factor. I don't understand. Unless relatively prime natural numbers only include common even prime factorization? Help! Now it's become my question..thanks
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Re: 1:if x and 10 are relatively prime natural numbers, then x [#permalink]
[color=#BF0000]you may have received the answer to these problems by now. I still want to share with you what I think, let me know what the solution is.

For problem 1

Prime numbers are numbers that can divide into 2 with a remender of 1.
I think that the answer to that problem is A

If you multiply 9*9 = 81, 10 + 81 = 91

91 will divide into 2 with remainder 1
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Re: 1:if x and 10 are relatively prime natural numbers, then x [#permalink]
What is the source of question. I have learnt a new term "relative prime number" and its definition.
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Re: 1:if x and 10 are relatively prime natural numbers, then x [#permalink]
Nice explanation +1
icandy wrote:
charles77479a wrote:
1:if x and 10 are relatively prime natural numbers, then x could be a multiple of
a: 9
b: 18
c:4
d:25
e:14

Relative prime numbers are numbers which have 1 as their Greatest common factor.

look at the Q, it says could be. lets look for which cannot be

18, 10 have 2 as a common divisor which is > 1

(4,10) (25,10) (14,10) all have divisors such as 2, 5 which are greater than 1. If the numbers themselves have GCF's other than 1, their multiples also will have GCF other than 1.

(9,10) have their greatest common factor as 1. even though (18,10) have 2 as common factor, 9 still serves our answer "could be"


2:the area of ADE is 12 square units. If B is the midpoint of AD and C is the midpoint of AE, what is the area of ABC.
a:2 s/u
b:3 s/u
c:3.5 s/u
d:4 square units
e: 6 square units

Once we figure out that these triangles are similar triangles, we need to

Area of large triangle = (s ^ 2) * area of small triangle

where s is similarity ratio. We see that each side of big triangle is twice the small triangle

12 = 4 * area of small triangle -> 3


I know the answer to these questions; however, i do not understand how to solve the problem. If someone could explain them in details, i would really appreciate it. Thank you very much.
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Re: 1:if x and 10 are relatively prime natural numbers, then x [#permalink]
dczuchta ,

The question 1 asks , then x could be a multiple of..it does not say X will be a multiple of .



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