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Re: Both a, b, and c are 3-digits integers, where a=b+c. Is the [#permalink]
I think ans is A

Statement 1 can only be true when there are no carry forwards from units to tens, and also from tens to hundreds. Though i have not checked out all the alternatives as it would take a lot of time, i personally feel sufficiently confident about this, and would rather have it answered wrong than waste time in attempting to check all alternatives.

If there are no carry forwards from tens to hundreds, the sum of hundreds digits of b and c will be equal to that of a.
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Re: Both a, b, and c are 3-digits integers, where a=b+c. Is the [#permalink]
Quote:
1). Tens' digit of a=tens' digit of b+tens' digit of c


the only thing that I can conclude from this statement is , nothing got carried from units place...but I cant tell whether anything got carried over to the hundreds place..

281
+372
------
653 <-- here tens digit of the result is still equal to the tens digit of b and tens digit of c

one more case

231
+321
------
552 <-- here nothing is carried forward still the statement 1 holds good.

I would say the answer be E.
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Re: Both a, b, and c are 3-digits integers, where a=b+c. Is the [#permalink]
skpMatcha wrote:
------
653 <-- here tens digit of the result is still equal to the tens digit of b and tens digit of c



tens digit is not equal to that of b+c

8+7 = 15 and not 5; and 15 is not one single digit. So no carry forward is ensured.
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Re: Both a, b, and c are 3-digits integers, where a=b+c. Is the [#permalink]
Thanks for the explanation. Looks like these notions are unique to GMAT.

like rounding to nearest number cant be recursive and only the digit next to the rounding position is rounded && and the example as this thread..

:)
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Re: Both a, b, and c are 3-digits integers, where a=b+c. Is the [#permalink]
vcbabu wrote:
. Both a, b, and c are 3-digits integers, where a=b+c. Is the hundreds' digit of number a equal to sum of that of b and c?
1). Tens' digit of a=tens' digit of b+tens' digit of c
2). Units' digit of a=units' digit of b + units' digit of c



I also think it should be A as there is no carry forward from the tens digit. Anyway whats the OA ?

Cheers
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Re: Both a, b, and c are 3-digits integers, where a=b+c. Is the [#permalink]
Hi Guys, can someone explain why answer is "A"?
Thx in advance



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