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M15-34

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Bunuel
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M15-34 [#permalink] New post   16 Sep 2014, 00:57
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78% (02:23) correct 23% (03:06) wrong based on 120 sessions
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In November, a company sold 3,000 units of Model A and 1,000 units of Model B. Model A contributed 60% to the company's total monthly sales revenue in dollars, while Model B contributed the remaining 40%. If the company had sold 1,000 fewer units of Model A than they actually did, what percentage of the total monthly sales revenue in dollars would have been attributed to Model A?

A. 48
B. 50
C. 52
D. 54
E. 55
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B
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Bunuel
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Re M15-34 [#permalink] New post   16 Sep 2014, 00:57
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Official Solution:

In November, a company sold 3,000 units of Model A and 1,000 units of Model B. Model A contributed 60% to the company's total monthly sales revenue in dollars, while Model B contributed the remaining 40%. If the company had sold 1,000 fewer units of Model A than they actually did, what percentage of the total monthly sales revenue in dollars would have been attributed to Model A?

A. 48
B. 50
C. 52
D. 54
E. 55


Suppose the total sales revenue in November was $100. In this case, Model A contributed $60 and Model B contributed $40.

If the company had sold 1,000 fewer units of Model A than they actually did, it would have sold only 2,000 units of Model A. This is 2/3 of the units of Model A that were actually sold. Consequently, Model A would have contributed 2/3 of its original contribution, amounting to $40. In this scenario, the total revenue would have been $40 + $40 = $80. Therefore, 50% of the total monthly sales revenue in dollars would have been attributed to Model A.


Answer: B
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Bunuel
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Re: M15-34 [#permalink] New post   22 Mar 2023, 02:18
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M15-34 [#permalink] New post   22 Feb 2024, 02:36
­Hi Bunuel,

Thank you for the question.

I looked up an algebraic approach for this question, and it made sense.

But I feel unsatisfied. I understand your solution, but I was wondering is there another way to word the solution, or another approach you could also take? I'm having difficulty grasping it. Any similar questions like this so I can practice using the methodology of your solution?

Thank you.
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Bunuel
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Re: M15-34 [#permalink] New post   22 Feb 2024, 05:12
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CoffeeNCream wrote:
­Hi Bunuel,

Thank you for the question.

I looked up an algebraic approach for this question, and it made sense.

But I feel unsatisfied. I understand your solution, but I was wondering is there another way to word the solution, or another approach you could also take? I'm having difficulty grasping it. Any similar questions like this so I can practice using the methodology of your solution?

Thank you.

­
You can check alternative explaantion here.
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Mauryashristi61
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M15-34 [#permalink] New post   13 Mar 2024, 07:17
 
CoffeeNCream wrote:
­Hi Bunuel,

Thank you for the question.

I looked up an algebraic approach for this question, and it made sense.

But I feel unsatisfied. I understand your solution, but I was wondering is there another way to word the solution, or another approach you could also take? I'm having difficulty grasping it. Any similar questions like this so I can practice using the methodology of your solution?

Thank you.

­
A = 3000
B = 1000

Its given for A - 3000  * cost/piece= 0.6* Revenue
Hence Revenue = 5000

For B - 1000 * cost/Piece = 0.4* Revenue
Cost/Piece = 2

So I can say 3000*1 ( qty * Cost for A ) + 1000*2 ( Qty * Cost for B )= 5000 ( Revenue )
If I reduce 1000 from A then I get Qty = 2000
Value = 2000*1 = 2000

Whereas for B Qty = 1000
Value = 1000* 2 = 2000

Total revenue = 2000 + 2000 = 4000
Hence A is contributing 50%
 ­
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