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Quant Question of the Day Chat

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Anki111
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:19
answer is strangely E
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Shrey612
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:20
Anki111 wrote:
A piece of carpet in the shape of a trapezoid has a smaller base measuring 50 inches and the larger base measuring 70 inches. What is the perimeter of the carpet?

(1) The area of the carpet is 450 square inches.
(2) The height of the carpet is 7.5 inches.

Can some one explain this? Why can’t one side be equal to the Height and the other side we can find with the help of Pythagoras Theorem. So, D should be sufficient. 50+70+s1+s2


Both statements are not sufficient to determine length of remaining sides.
E

Posted from my mobile device
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Anki111
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:21
thats what i thought too

can anyone explain ?
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sg_mba
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:22
Anki111 wrote:
Can some one explain this? Why can’t one side be equal to the Height and the other side we can find with the help of Pythagoras Theorem. So, D should be sufficient. 50+70+s1+s2

Then in that case it will become a specific trapezoid. And we should solve the question with general shape. Not assuming anything by ourself

Answer is E
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Nikhil418
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:23
Is that a 700+ question?
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Anki111
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:24
if it was isosceles trapezoid, then we can say we have s1=s2. but can it be D the ?
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Ankyt13
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:25
True. Only for Isosceles the answer can be D. Otherwise there is no way to know where the perpendicular line would cut the base.
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Anki111
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:26
and for isosceles we know that both the cut parts are equal ? correct?
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Ami0Trafalgar
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:27
the other two sides can have 2 different acute angles. if you assume the sides to be the same then the trapezoid is case specific by assumption and not data given.

Hence it will be E

Anki111 wrote:
if it was isosceles trapezoid, then we can say we have s1=s2. but can it be D the ?

Exactly
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Nikhil418
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:28
Nikhil418 wrote:
Is that a 700+ question?

Hi please tell the level of the question as well if you dont mind
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Ami0Trafalgar
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:28
i dont think it’s 700+

probably 650ish ?
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Anki111
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:28
yeaaa it is 650-700 level
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 00:56
Anki111 wrote:
can anyone explain ?

I believe you are assuming its a regular trapezoid, in which case you can use the the height and pythogras but this is not stated in the question

Just that it is a trapezoid shape
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 01:43
Can some one explain this? Why can’t one side be equal to the Height and the other side we can find with the help of Pythagoras Theorem. So, D should be sufficient

In ΔABC, point D lies on the side AB between vertices A and B. If CD = CB, is AD > BC?

(1) ∠ADC = 110°

(2) ∠ACD = 30°
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   Updated on: 15 Jun 2023, 01:55
For any line to be height, it has to be perpendicular drawn from vertex to opposite side. It’s not said that CD is perpendicular. It’s just a line.

Is the answer C?

Originally posted by Ankyt13 on 15 Jun 2023, 01:50.
Last edited by Ankyt13 on 15 Jun 2023, 01:55, edited 1 time in total.
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   Updated on: 15 Jun 2023, 02:02
YES ANSWER IS C

CAN you explain

Originally posted by Anki111 on 15 Jun 2023, 02:01.
Last edited by Anki111 on 15 Jun 2023, 02:02, edited 1 time in total.
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   Updated on: 15 Jun 2023, 02:05
C

Side opposite to greater angle is greater

Originally posted by Shobhit28 on 15 Jun 2023, 02:04.
Last edited by Shobhit28 on 15 Jun 2023, 02:05, edited 1 time in total.
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Ankyt13
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 02:10
Statement 1: It provides angle ADC. Through that you can conclude that angle CDB is 70 (180-110). As CD equals CB. It’s an isosceles triangle. You cannot conclude anything further.

Statement 2: Angle ACD is 30 and therefore nothing else can be concluded regarding the sides AD and BC from it.

Combining both you can find that angle ACB is 30+40 i.e 70 degree. Therefore Triangle CDB and ABC are similar. Two angles are similar and common base. Therefore AD is not greater than BC.
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am79021
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 02:22
Ankyt13 wrote:
Statement 1: It provides angle ADC. Through that you can conclude that angle CDB is 70 (180-110). As CD equals CB. It’s an isosceles triangle. You cannot conclude anything further. Statement 2: Angle ACD is 30 and therefore nothing else can be concluded regarding the sides AD and BC from it. Combining both you can find that angle ACB is 30+40 i.e 70 degree. Therefore Triangle CDB and ABC are similar. Two angles are similar and common base. Therefore AD is not greater than BC.

"Two angles are similar and common base. Therefore AD is not greater than BC" - Can you explain how can we conclude this?
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Re: Quant Question of the Day Chat [#permalink] Quant Question of the Day Chat   15 Jun 2023, 02:42
am79021 wrote:
"Two angles are similar and common base. Therefore AD is not greater than BC" - Can you explain how can we conclude this?

The traingles are similar and We know that D is a point in AB so
AD< AB
AD<AC (as AB=AC)
For an Isosceles traingle third side cannot be greater than equal sides. If it were greater then it won’t be isosceles triangle.
Therefore AD < BC (as AC is greater than BC). Hope it helps.
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