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# Quant Question of the Day Chat

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Math Expert
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Re: Quant Question of the Day Chat [#permalink]
 Data Sufficiency Butler: May 2024 May 24 DS 1 DS 2
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Math Expert
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Re: Quant Question of the Day Chat [#permalink]
 Problem Solving Butler: April 2023 May 24 PS 1 PS 2
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Manager
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Re: Quant Question of the Day Chat [#permalink]
The answer is A or E?
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Re: Quant Question of the Day Chat [#permalink]
The range is from -14 to 26, so look for the answer that contains this range. x>-100 contains the range, so A is correct.
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Re: Quant Question of the Day Chat [#permalink]
But x>-100 means it’s greater than 26 as well which breaks the domain of inequality

I got Q10 as A, Q11 as D and need help in Q12.
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Re: Quant Question of the Day Chat [#permalink]
Is the answer E for 12?
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Re: Quant Question of the Day Chat [#permalink]
PrabhatKC wrote:
But x>-100 means it’s greater than 26 as well which breaks the domain of inequality

It does not matter, We are not looking for exact range. We are looking at what MUST be true. For example: if a number is 2<x<4, it MUST be true that it is positive, that is x>0

SATYAM7777 wrote:
Is the answer E for 12?

It would be B....we can divide both sides of inequality a^2x>a^2y by a postive value a^2 without changing the inequality sign, so a^2x/a^2 > a^2y/a^2 or x>y.
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Re: Quant Question of the Day Chat [#permalink]
chetan2u wrote:
It would be B....we can divide both sides of inequality a^2x>a^2y by a postive value a^2 without changing the inequality sign, so a^2x/a^2 > a^2y/a^2 or x>y.

Oh yeah. Right.

These types of questions aren’t asked anymore , right ?
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Re: Quant Question of the Day Chat [#permalink]
chetan2u wrote:
It would be B....we can divide both sides of inequality a^2x>a^2y by a postive value a^2 without changing the inequality sign, so a^2x/a^2 > a^2y/a^2 or x>y.

So why it’s not D, each sufficient, cause

ax>ay, a also can be cancelled leaving x>y

I have two more doubts for today. 19 and 21.
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Re: Quant Question of the Day Chat [#permalink]
PrabhatKC wrote:
So why it’s not D, each sufficient, cause

ax>ay, a also can be cancelled leaving x>y

Just a can’t be canceled because a can be negative also. However a^2 can be canceled because a^2 is always positive

I’m not a fan of cancelling out though. You can just do a(x-y) >0. Now if a is negative then (x-y) will be negative and if a is positive then (x-y) will be positive
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Re: Quant Question of the Day Chat [#permalink]
Is average and abligation in the syllabus??
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Re: Quant Question of the Day Chat [#permalink]
average is there, no abligation

PrabhatKC wrote:
I have two more doubts for today. 19 and 21.

Dear, which book is this?
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Re: Quant Question of the Day Chat [#permalink]
hey guys, i took the practice GMAT exam, managed to do good in verbal but absolutely terrible on the quant section. Any tips on how to improve?
Intern
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Re: Quant Question of the Day Chat [#permalink]
ara.mbs wrote:
hey guys, i took the practice GMAT exam, managed to do good in verbal but absolutely terrible on the quant section. Any tips on how to improve?

I think you should go with the basics first, learn the basics of arithmetic, algebra, number systems , and then try to solve at least 20 questions a day, using this strategy I also ended up in my recent mock 715 overall.
Intern
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Re: Quant Question of the Day Chat [#permalink]
Hey everyone ,

Suggest me some mock test resources
And approach for handling RC
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Re: Quant Question of the Day Chat [#permalink]
ara.mbs wrote:
hey guys, i took the practice GMAT exam, managed to do good in verbal but absolutely terrible on the quant section. Any tips on how to improve?

Manager
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Re: Quant Question of the Day Chat [#permalink]
krish13ts wrote:
Dear, which book is this?

Jamborees Quant Book
Re: Quant Question of the Day Chat [#permalink]
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