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# Real numbers x, y, and z satisfy the inequalities [m]0<x<1[/m], [m]-1<

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Manager
Status: students
Joined: 08 Mar 2019
Posts: 93
GPA: 3.9
WE: Account Management (Accounting)
Real numbers x, y, and z satisfy the inequalities [m]0<x<1[/m], [m]-1<  [#permalink]

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18 Mar 2019, 05:48
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Difficulty:

35% (medium)

Question Stats:

71% (01:31) correct 29% (02:00) wrong based on 21 sessions

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Real numbers x, y, and z satisfy the inequalities $$0<x<1$$, $$-1<y<0$$, and $$1<z<2$$. Which of the following numbers is necessarily positive?

(A)$$y+x^2$$

B) $$y+xz$$

(C)$$y+y^2$$

(D)$$y+2y^2$$

E) $$y+z$$
NUS School Moderator
Joined: 18 Jul 2018
Posts: 1024
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: Real numbers x, y, and z satisfy the inequalities [m]0<x<1[/m], [m]-1<  [#permalink]

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18 Mar 2019, 13:13
From the given info.
X and Z are always positive.
Y can be positive or negative.

Looking at the options.
Only E will give always be positive as Z is always greater than 1 and Y is always greater than -1.

E is the answer
Re: Real numbers x, y, and z satisfy the inequalities [m]0<x<1[/m], [m]-1<   [#permalink] 18 Mar 2019, 13:13
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# Real numbers x, y, and z satisfy the inequalities [m]0<x<1[/m], [m]-1<

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