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By plugging in different value we can see we can not conclude anything.

Hence answer is E.

Lets say first set is A{a,b,c} and second set is B{x,y,z}

so is a+b+c > x+y+z ?

Statement 1: The median of Set A is greater than the median of set Set B.
A{1,5,6} and B{4,4,10} ---No
A{4,5,10} and B{1,4,10} ---Yes
Insufficient

Statement2: The mode of Set A is greater than the mode of Set B.
A{2,2,3} and B{1,1,10} ---No
A{8,8,9} and B{1,1,2} ---Yes

Statement 1 and 2: We again get answer as Yes and No.

So answer is E.
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Bunuel

Tough and Tricky questions: Statistics.



Set A and Set B each contain three whole numbers ranging from 1 to 10. With regard to the data contained in each set, is the arithmetic mean of Set A greater than the arithmetic mean of Set B?

(1) The median of Set A is greater than the median of set Set B.
(2) The mode of Set A is greater than the mode of Set B.

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The correct answer is E.
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Bunuel

Tough and Tricky questions: Statistics.



Set A and Set B each contain three whole numbers ranging from 1 to 10. With regard to the data contained in each set, is the arithmetic mean of Set A greater than the arithmetic mean of Set B?

(1) The median of Set A is greater than the median of set Set B.
(2) The mode of Set A is greater than the mode of Set B.

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Source: Chili Hot GMAT

A =(x,y,z)
B =(k,l,m)
(1) assume y is median of A, and l is median of B. cant conclude (x+y+z)/3 > (k+l+m)/3 => not sufficient
(2) x,y,...m are different. can't conclude => not sufficient
(1)+ (2) not sufficient =>E
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This is a very good question. I understand how statements A and B are insufficient. However, in everyone's explanations, I don't understand how you tested the statements COMBINED. Anyone care to explain?
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