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# Set S is composed of consecutive multiples of 3. Set T is

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Current Student
Joined: 11 May 2008
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Set S is composed of consecutive multiples of 3. Set T is [#permalink]

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29 Aug 2008, 00:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Set S is composed of consecutive multiples of 3. Set T is composed of consecutive multiples of 6. Each set contains more than one element. Is the median of set S bigger than the median of set T?

1. The least element in either set is 6
2. Set T contains twice as many elements as set S

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Director
Joined: 03 Sep 2006
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29 Aug 2008, 00:55
from ( 1 ) you can't answer because it may or may not be bigger, but if you know ( 2 ) as well as ( 1 ) then you can answer the question.

Thus "C"

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Current Student
Joined: 11 May 2008
Posts: 555

Kudos [?]: 222 [0], given: 0

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29 Aug 2008, 01:31
Why is B not suff??
i think i know why.. but anyway...

let me see if what i have in mind is correct...

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Director
Joined: 23 Sep 2007
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29 Aug 2008, 02:23
arjtryarjtry wrote:
Why is B not suff??
i think i know why.. but anyway...

let me see if what i have in mind is correct...

T can be 6, 12, 18, 24, 30, 36
S can be 300, 303, 306

OR

T can be 6, 12, 18, 24, 30, 36
S can be 3, 6, 9

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Joined: 07 Nov 2007
Posts: 1792

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Location: New York

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29 Aug 2008, 07:48
arjtryarjtry wrote:
Why is B not suff??
i think i know why.. but anyway...

let me see if what i have in mind is correct...

Set T can have all -ve elements and S +ve Median of S>Median T
Set S can have all -ve elements and T +ve Median of T>Median S
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Smiling wins more friends than frowning

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SVP
Joined: 29 Aug 2007
Posts: 2472

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29 Aug 2008, 08:20
arjtryarjtry wrote:
Set S is composed of consecutive multiples of 3. Set T is composed of consecutive multiples of 6. Each set contains more than one element. Is the median of set S bigger than the median of set T?

1. The least element in either set is 6
2. Set T contains twice as many elements as set S

1: Do not know the no of elements in each set.
2: do not know whether S or T has -ve or +ve elements.

1&2: sufficient as we know the first elelment is 6 and T has twice as many.

so Median T > Median S.

good one.
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GT

Kudos [?]: 843 [0], given: 19

Re: sets   [#permalink] 29 Aug 2008, 08:20
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