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Steve bought some apples at a cost of $.60 each and some oranges at a

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Steve bought some apples at a cost of $.60 each and some oranges at a  [#permalink]

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New post 21 May 2017, 11:20
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89% (01:27) correct 11% (01:54) wrong based on 39 sessions

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Steve bought some apples at a cost of $.60 each and some oranges at a cost of $.50 each. If he paid a total of $4.10, how many apples did Steve buy?

(1) The total number of apples and oranges Steve bought was 8.
(2) Steve bought seven times as many oranges as apples.

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Re: Steve bought some apples at a cost of $.60 each and some oranges at a  [#permalink]

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New post 21 May 2017, 23:27
Bunuel wrote:
Steve bought some apples at a cost of $.60 each and some oranges at a cost of $.50 each. If he paid a total of $4.10, how many apples did Steve buy?

(1) The total number of apples and oranges Steve bought was 8.
(2) Steve bought seven times as many oranges as apples.



Per qsn., \(0.6*A + 0.5*O = 4.1\)

=> \(6A + 5O = 41\)
To achieve 41, we can have either \(6*6 + 5*1\) OR \(6*1 + 5*7\).

Stmt 1 : \(A+O = 8\)
This matches the calculation : 6*1 + 5*7 = 41
We also could've used linear eqn in 2 variables to solve. Sufficient.


Stmt 2 : \(7A = O\) OR \(7A - O = 0\)
This again is in line with the calculation : \(6*1 + 5*7 = 41\)

Hence D.
GMAT Club Bot
Re: Steve bought some apples at a cost of $.60 each and some oranges at a &nbs [#permalink] 21 May 2017, 23:27
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