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21 May 2017, 11:20
00:00

Difficulty:

25% (medium)

Question Stats:

86% (01:04) correct 14% (01:25) wrong based on 37 sessions

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Steve bought some apples at a cost of $.60 each and some oranges at a cost of$.50 each. If he paid a total of $4.10, how many apples did Steve buy? (1) The total number of apples and oranges Steve bought was 8. (2) Steve bought seven times as many oranges as apples. _________________ Manager Joined: 24 Dec 2016 Posts: 78 Location: India Concentration: Finance, General Management WE: Information Technology (Computer Software) Re: Steve bought some apples at a cost of$.60 each and some oranges at a [#permalink]

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21 May 2017, 23:27
Bunuel wrote:
Steve bought some apples at a cost of $.60 each and some oranges at a cost of$.50 each. If he paid a total of $4.10, how many apples did Steve buy? (1) The total number of apples and oranges Steve bought was 8. (2) Steve bought seven times as many oranges as apples. Per qsn., $$0.6*A + 0.5*O = 4.1$$ => $$6A + 5O = 41$$ To achieve 41, we can have either $$6*6 + 5*1$$ OR $$6*1 + 5*7$$. Stmt 1 : $$A+O = 8$$ This matches the calculation : 6*1 + 5*7 = 41 We also could've used linear eqn in 2 variables to solve. Sufficient. Stmt 2 : $$7A = O$$ OR $$7A - O = 0$$ This again is in line with the calculation : $$6*1 + 5*7 = 41$$ Hence D. Re: Steve bought some apples at a cost of$.60 each and some oranges at a   [#permalink] 21 May 2017, 23:27
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