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The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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Updated on: 27 Feb 2019, 06:49
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The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of the perpendicular from D to AB is 1.5cm. Find the length of the perpendicular from D to BC? a) 1.5 cm b) 2 cm c) 3 cm d) 4 cm e) 6 cm
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Originally posted by jackfr2 on 27 Feb 2019, 06:29.
Last edited by Bunuel on 27 Feb 2019, 06:49, edited 1 time in total.
Renamed the topic and edited the question.



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Re: The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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09 Mar 2019, 08:28
Area of the logram ABCD = base * height Base AB * Height ( length of perpendicular from D to base AB) = 4 * 1.5 = 6 but this is also equal to Base BC * ( length of perpendicular from D to base BC ) = 3 * x
this implies x = 6/3 = 2.



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Re: The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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09 Mar 2019, 13:05
S = h*AB S = 1.5*4 S = 6cm² S = x*BC 6 = x*3 x = 2cm
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Re: The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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28 Feb 2019, 00:20
Could someone please post the answer and approach? TIA.
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Re: The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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08 Mar 2019, 22:44
Bunuel, @chetanu can you pls answer this question



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Re: The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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09 Mar 2019, 08:32
It is not a 700level question.



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Re: The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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09 Mar 2019, 08:39
we need to equat the area of parallelogram with base AB to base BC .
so 1.5*AB= BC*h 1.5*4= 3*h
so h = 2
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Re: The parallelogram ABCD is such that AB=4cm, AD=3cm and the length of
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09 Mar 2019, 08:39






