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The product of all the prime numbers less than 20 is closest to which
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02 Jul 2012, 01:21
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48% (01:09) correct 52% (01:14) wrong based on 3592 sessions
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Re: The product of all the prime numbers less than 20 is closest to which
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02 Jul 2012, 01:22




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Re: The product of all the prime numbers less than 20 is closest to which
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25 Oct 2013, 03:45
I have approached in the following way:
2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 = 10 x 21x 11 x 13 x 17 x 19 = 10 x 10 x 2.1 x 10 x 1.1 x 10 x 1.3 x 10 x 1.7 x 10 x 1.9 = 10^6 x (2.1 x1.1 x 1.3 x 1.7 x 1.9)
The approximation of the (2.1 x 1.7 x 1.9 x 1.3 x 1.1) will be close to 10, so the answer is 10^7




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Re: The product of all the prime numbers less than 20 is closest to which
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Updated on: 02 Jul 2012, 02:39
Hi,
Difficulty level: 650
Product of prime numbers less than 20 = 2*3*5*7*11*13*17*19 =(2*5)*3*(7*13)*(11*17)*19 =3*10*91*189*19 ~(30)*(90*19)*190 ~5700*1710 ~5700*1700 ~9690000 \((=10^6)\)
Thus, Answer is (D)
Regards,
Originally posted by cyberjadugar on 02 Jul 2012, 02:17.
Last edited by cyberjadugar on 02 Jul 2012, 02:39, edited 2 times in total.



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Re: The product of all the prime numbers less than 20 is closest to which
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02 Jul 2012, 02:25
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectThe product of all the prime numbers less than 20 is closest to which of the following powers of 10 ? (A) 10^9 (B) 10^8 (C) 10^7 (D) 10^6 (E) 10^5 Diagnostic Test Question: 15 Page: 22 Difficulty: 650 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you! The product is \(2*3*5*7*11*13*17*19 = 10 * 21 * 11*(13*17) * 19 \approx10*20*10*15^2*20=900*10^4\approx10^7\). Therefore, answer C
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Re: The product of all the prime numbers less than 20 is closest to which
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02 Jul 2012, 02:45
Hi,
The magnitude of error depends on the approximation done in the question.
For example: 51*671=34221 50*671=33550 (error = 671) 51*670=34170 (error = 51)
Thus, the when the larger number is approximated the error is less.
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Re: The product of all the prime numbers less than 20 is closest to which
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02 Jul 2012, 11:58
2*3*5*7*11*13*17*19 = 210*(10+1)(10+3)(10+7)(10+9) 210 ~ 10*10*2 So the original equation will be equivalent to 10*10*2*(10+1)(10+3)(10+7)(10+9) The highest order of the equation will be 10^6, and other part of expression will not make it closer to 10^7. I have solved it mostly on hunch, no sure how correct I am.



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Re: The product of all the prime numbers less than 20 is closest to which
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05 Mar 2014, 10:48
Similar to Bunuel's first approach: I thought it was easiest to just do : 2*3*5*7 = 210 11 roughly 10 13 roughly 10 17 roughly 20 19 roughly 20 so 210*10*10*20*20 = 8*10^6 = 10^7



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Re: The product of all the prime numbers less than 20 is closest to which
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06 Mar 2014, 20:40
Product of Prime no between 1 & 20 = (2*3*5*7)*(11*13)* (17*19) 210 * 143 * 323 \((10^2+10) * (10^1+43) * (10^3+23)\) \((10^3+4300+10^2+430) * (10^3+23)\) \(5830 * (10^3+23)\) 5830000 + 134090 = 6974090 this is near to 10^7 Answer = C
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Re: The product of all the prime numbers less than 20 is closest to which
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21 Jun 2015, 02:36
Here's my solution 2*3*5*7*11*13*17*19 1) 2*3*5*19 ~ 30*20 2) 11*13 ~ 140 3) 7*17 ~ 120 SO we have 600*140*120 = 10^4*168*6 (168*6 ~ 1000) > ~ 10^4*10^3 ~10^7 Method 22*3*5*7*11*13*17*19 = 2*5*11*19*(107)(10+7)(103)(10+3) ~ 2*10*10*10*50*80=100*10*10*10*10*8 ~\(10^7\) Answer (D)
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The product of all the prime numbers less than 20 is closest to which
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07 Mar 2016, 08:42
Wayxi wrote: The product of all the prime numbers less than 20 is closest to which of the following powers of 10 ?
a. 10^9 b. 10^8 c. 10^7 d. 10^6 e. 10^5
Quickly approximate 2, 3, 5, 7, 11, 13, 17, 19 Make groups 2*5 = 10 3*17 = 50 (approximately) 7*13 = 100 (approximately) 11*19 = 200 (approximately) So you make 7 zeroes (the 2 and the 5 also make a 0). When you multiply all these, the answer will be close to 10^7
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Re: The product of all the prime numbers less than 20 is closest to which
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12 Jul 2017, 16:02
Bunuel wrote: The product of all the prime numbers less than 20 is closest to which of the following powers of 10 ?
(A) 10^9 (B) 10^8 (C) 10^7 (D) 10^6 (E) 10^5 We need to determine the product of: 2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 Let’s group some of these numbers to get powers of 10: 5 x 19 is about 100 = 10^2 So, we are left with: 2 x 3 x 7 x 11 x 13 x 17 7 x 13 is about 100 = 10^2 So, we are left with: 2 x 3 x 11 x 17 2 x 3 x 17 is about 100 = 10^2 Finally, we have 11, which is about 10 = 10^1. Thus, the product of all the prime numbers less than 20 is closest to 10^2 x 10^2 x 10^2 x 10^1 = 10^7. Answer: C
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Re: The product of all the prime numbers less than 20 is closest to which
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23 Jan 2018, 16:41
Bunuel wrote: The product of all the prime numbers less than 20 is closest to which of the following powers of 10 ? (A) 10^9 (B) 10^8 (C) 10^7 (D) 10^6 (E) 10^5 Diagnostic Test Question: 15 Page: 22 Difficulty: 650 It is a good idea to have the representation of numbers in the solution in terms of that in the problem. Primes below 20 are 2,3,5,7,11,13,17,19. So we have (108)(107)(105)(103)(10+1)(10+3)(10+7)(10+9) Rearranging we have (108)*(10+9) * (107)*(10+7) * (103)*(10+3) *(105)*((10+1) Approximately these 4 pairs are: 90*50*90*50= approximately 10^7
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Re: The product of all the prime numbers less than 20 is closest to which
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02 May 2018, 08:05
Bunuel wrote: The product of all the prime numbers less than 20 is closest to which of the following powers of 10 ?
(A) 10^9 (B) 10^8 (C) 10^7 (D) 10^6 (E) 10^5
Since the answer choices are very spread apart (each number is 10 times greater than the next answer choice), we can be somewhat AGGRESSIVE with our estimation. We have the product (2)(3)(5)(7)(11)(13)(17)(19) Let's see if we can group the numbers to get some approximate powers of 10First (2)(5)=10, so we get (2)(3) (5)(7)(11)(13)(17)(19) = (10)(3)(7)(11)(13)(17)(19) Next, 11 is close enough to 10, so we get: (10)(3)(7) (11)(13)(17)(19) ≈ (10)(3)(7) (10)(13)(17)(19) [ approximately] Next, (7)(13)=91, which is pretty close to 100. So we get (10)(3) (7)(10) (13)(17)(19) ≈ (10)(3) (100)(10)(17)(19) [ approximately] Finally, 3(17)=51, and (51)(19) is very close to (51)(20), which is very close to 1000 So,(10) (3)(100)(10) (17)(19) ≈ (10) (1000)(100)(10) ≈ 10,000,000 Since 10,000,000 = 10^7, the best answer is C Cheers, Brent
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