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Re: The ratio of a two digit number to a number formed by reversing its di [#permalink]
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chetan2u wrote:
DisciplinedPrep wrote:
The ratio of a two digit number to a number formed by reversing its digits is 4:7. Which of the following is the sum of all the numbers of all such pairs?

A. 110
B. 200
C. 330
D. 88
E. 770


Number = 10a+b and its reverse = 10b+a..
So, 10a+b:10b+a=4:7......7(10a+b)=4(10b+a).....70a+7b=40b+4a.....66a=33b....b=2a...

So, numbers are (a)(2a).......12, 24, 36, 48...
Sum = 12+24+36+48+21+42+63+84=330

C

­chetan2u Why do we consider 21,42,63 and 84? The ratio of those numbers and their reversed digits is 7:4 and not 4:7
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Re: The ratio of a two digit number to a number formed by reversing its di [#permalink]
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DisciplinedPrep wrote:
The ratio of a two digit number to a number formed by reversing its digits is 4:7. Which of the following is the sum of all the numbers of all such pairs?

A. 110
B. 200
C. 330
D. 88
E. 770

\(\frac{­10a + b}{10b + a} = \frac{4}{7}\)­

Or, \(70a + 7b = 40b + 4a\)

Or, \(66a = 33b\)

Or, \(2a = b\)

Now plug in possible values of a and b for a 2 digit no -
Attachment:
Screenshot 2024-03-11 200935.png
Screenshot 2024-03-11 200935.png [ 2.04 KiB | Viewed 902 times ]
neglect a = 10 and b =5 as 2 digit no can not be formed when a  = 10

Now, find 10a  + b
Attachment:
10a + b.png
10a + b.png [ 1.68 KiB | Viewed 893 times ]


Again form 10b + a 
Attachment:
10b + a.png
10b + a.png [ 1.58 KiB | Viewed 883 times ]


Now add (10a + b) + (10b + a) : 
Attachment:
10a + b + 10b +a.png
10a + b + 10b +a.png [ 4.1 KiB | Viewed 879 times ]
 

Here all the values : \(33 + 66 + 99 + 132 = 330\), Answer must be (C)



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Re: The ratio of a two digit number to a number formed by reversing its di [#permalink]
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Guntabulla wrote:
chetan2u wrote:
DisciplinedPrep wrote:
The ratio of a two digit number to a number formed by reversing its digits is 4:7. Which of the following is the sum of all the numbers of all such pairs?

A. 110
B. 200
C. 330
D. 88
E. 770


Number = 10a+b and its reverse = 10b+a..
So, 10a+b:10b+a=4:7......7(10a+b)=4(10b+a).....70a+7b=40b+4a.....66a=33b....b=2a...

So, numbers are (a)(2a).......12, 24, 36, 48...
Sum = 12+24+36+48+21+42+63+84=330

C

­chetan2u Why do we consider 21,42,63 and 84? The ratio of those numbers and their reversed digits is 7:4 and not 4:7


Hi

The numbers are 12, 24, 36 and 48 itself in the solution. However you have to add the pairs that is 12 and 21 plus 36 and 63 and so on.

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Re: The ratio of a two digit number to a number formed by reversing its di [#permalink]
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