Three couples need to arranged in a row for a group photo. If the coup

48
8 ways each group can be arranged internally & there are such 6 combination of couples possible.
.•. 6×8=48

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D. 48

Since as group arrangements are 6 x couple arrangement within themselves 2x2x2

We need to determine in how many ways three couples can be arranged when each couple must stay together.

We can arrange the three couples as follows:

[A-B], [C-D], [E-F].

(Note: Since each couple must remain together, we have expressed each couple in a bracket.)

Since we have 3 brackets, we can arrange those 3 brackets in 3! or 6 ways. However, we must account for the individual arrangements of each couple, i.e., the number of arrangements within each individual bracket.

Couple AB can be arranged in 2! or 2 ways, couple CD can be arranged in 2! or 2 ways, and couple EF can be arranged in 2! or 2 ways.

Thus, the couples can be arranged in 6 x 2 x 2 x 2 = 48 ways.

Answer: D

I went with the construction:

3! (3 couples) * 2! * 2! * 2! = 48

2! signifies within couple ways.

Upon reading some other ways it seems slot method also works

6 * 1 * 4 * 1 * 2 * 1 = 48