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Re: Is x + y odd? (1) 2y + x is even (2) 2x + y is even­ [#permalink]
stonecold wrote:
Is x+y odd?

(1) 2y + x is even
(2) 2x + y is even


FROM STATEMENT - I ( INSUFFICIENT )

2y = Even

Since, 2y + x = Even

x = Even ( Because Even + Even = Even & Odd + Odd =Even )

But what about y ? It can be Odd/Even

FROM STATEMENT - II ( INSUFFICIENT )

2x = Even

Since, 2x + y = Even

y = Even ( Because Even + Even = Even & Odd + Odd =Even )

But what about x ? It can be Odd/Even

FROM STATEMENT I & II ( SUFFICIENT )

From I - x = Even
From II - y = Even

Thus, x + y = Even..

Hence, BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked, answer will be (C)

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Re: Is x + y odd? (1) 2y + x is even (2) 2x + y is even­ [#permalink]
3x + 3y = even

3 (x + y) = even

The sum of (x + y) could (theoretically) take a fractional amount, such as 4/3

But in such a case for each statement to be sufficient

2x + y = even

2y + x = even

X = Y = 2/3 ———>

2(2/3) + 2/3 = 4/3 + 2/3 = 6/3 = 2, an even integer.

Even if we try to make X and Y fractional amounts, they are still not Odd Integers.

X + y = fractional amount, such as 4/3

Or

X and Y are integers, in which case (x + y ) = even integer

In either case, the sum of (x + y) can never be an Odd integer if:

3 * (x + y) = even integer

C —- definitely NO

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Re: Is x + y odd? (1) 2y + x is even (2) 2x + y is even­ [#permalink]
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Re: Is x + y odd? (1) 2y + x is even (2) 2x + y is even­ [#permalink]
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