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Trains A and B traveled the same 100-mile route. If Train A took 4 hou

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Trains A and B traveled the same 100-mile route. If Train A took 4 hou  [#permalink]

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New post 26 Sep 2018, 04:09
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86% (01:25) correct 14% (67:33) wrong based on 69 sessions

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Trains A and B traveled the same 100-mile route. If Train A took 4 hours and Train B traveled at an average speed 25 percent more than the average speed of Train A, how many hours did it take Train B to travel the route?


(A) 5/3
(B) 2
(C) 16/5
(D) 18/5
(E) 4

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Re: Trains A and B traveled the same 100-mile route. If Train A took 4 hou  [#permalink]

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New post 28 Sep 2018, 08:05
1
Train A drove at a 25mph.

Train B drove at 25% more. This translates into \(\frac{5}{4}\)\(*25\)\(=\frac{125}{4}\)

\(Time=\frac{Distance}{Speed}\)

\(100*\frac{4}{125}\)=\(\frac{16}{5}\)
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Trains A and B traveled the same 100-mile route. If Train A took 4 hou  [#permalink]

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New post 13 Oct 2018, 04:17
Let A drove at speed = 100 mph then B drove at speed will be 25% more = 125 mph
Distance drove by A= 100*4
Distance drove by B= 125*B
As, distance will be same
100*4=125*B, B= 16/5 hrs

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Re: Trains A and B traveled the same 100-mile route. If Train A took 4 hou  [#permalink]

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New post 13 Oct 2018, 05:26
Bunuel wrote:
Trains A and B traveled the same 100-mile route. If Train A took 4 hours and Train B traveled at an average speed 25 percent more than the average speed of Train A, how many hours did it take Train B to travel the route?


(A) 5/3
(B) 2
(C) 16/5
(D) 18/5
(E) 4


Find V1 = 100/4 = 25

T2 = 100/(25*5/4) = (100 * 4)/(25*5) = (25*4*4)/(25*5) = 16/5

Answer choice C

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Re: Trains A and B traveled the same 100-mile route. If Train A took 4 hou &nbs [#permalink] 13 Oct 2018, 05:26
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