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Two liquids A and B are in the ratio 5:1 in container 1 and in the

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Two liquids A and B are in the ratio 5:1 in container 1 and in the [#permalink]

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Two liquids A and B are in the ratio 5:1 in container 1 and in the ratio 1:3 in container 2. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1:1?

(A) 2:3
(B) 4:3
(C) 3:2
(D) 3:4
(E) 1:1

Source: Aristotle.
[Reveal] Spoiler: OA

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Re: Two liquids A and B are in the ratio 5:1 in container 1 and in the [#permalink]

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New post 22 Jul 2017, 15:16
Let's say X amount of Liquid in container 1 is mixed with Y amount of Liquid in container 2

so

\(\frac{5x}{6}\) + \(\frac{y}{4}\)= \(\frac{x + y}{2}\)

4x = 3y

\(\frac{x}{y}\) = \(\frac{3}{4}\)
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Re: Two liquids A and B are in the ratio 5:1 in container 1 and in the [#permalink]

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Gnpth wrote:
Two liquids A and B are in the ratio 5:1 in container 1 and in the ratio 1:3 in container 2. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1:1?

(A) 2:3
(B) 4:3
(C) 3:2
(D) 3:4
(E) 1:1

Source: Aristotle.


Lets assume the same quantity of the liquid in both the containers : 12 units.
Container 1 contains 10 units of liquid A and 2 units of liquid B
Container 2 contains 3 units of liquid A and 9 units of liquid B

Since the liquid in both the containers need to be mixed, such that the resulting
liquid has a ratio of 1:1(unit of liquid A : unit of liquid B)

Since the concentration of Liquid A must be equal to concentration of Liquid B
from both the containers.
\(10x + 3y = 2x + 9y\)
\(8x = 6y\)
\(\frac{x}{y} = \frac{3}{4}\)(Option D)
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Re: Two liquids A and B are in the ratio 5:1 in container 1 and in the [#permalink]

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New post 22 Jul 2017, 23:08
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Re: Two liquids A and B are in the ratio 5:1 in container 1 and in the [#permalink]

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Container 1:
Let each part be x.
Vol of A= 5x ; Vol of B= x ; Total Vol= 6x.

Container 2:
Let each part be y.
Vol of A= y ; Vol of B= 3y; Total Vol= 4y.

After Mixing:
Vol of A= 5x + y
Vol of B= x + 3y
As Ratio of A:B is 1:1, hence
5x+y = x+3y
2x = y
So,
Ratio of Total Vol 1 : Total Vol 2 =
6x / 4y = 6x / 4(2x) = 6/8 = 3/4.
Hence, Ans is Option D

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Re: Two liquids A and B are in the ratio 5:1 in container 1 and in the [#permalink]

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New post 05 Sep 2017, 20:04
Gnpth wrote:
Two liquids A and B are in the ratio 5:1 in container 1 and in the ratio 1:3 in container 2. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1:1?

(A) 2:3
(B) 4:3
(C) 3:2
(D) 3:4
(E) 1:1

Source: Aristotle.


A in container 1 represents 5/6 of its entire content. In the same way, A represents 1/4 of the content of container 2.

Now we want both A and B to represent each 1/2 of the new container (let's call it H).

So, for container 1 let's call the proportion of liquid A "x" and "y" for the other container, being y = 1 - x

We'll have: 5/6*x + 1/4*(1-x) = 1/2

If you solve it, you'll get: x = 3/7.

This means that liquid A from container 1 will occupy 3/7 of the total amount of liquid A in H. Liquid A from container 2 will occupy 4/7.

The same will happen with liquid B (1/2 * 3/7 + 3/4 * 4/7 = 1/2).

Thus, the asked ratio will be 3:4 (answer D).

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Re: Two liquids A and B are in the ratio 5:1 in container 1 and in the [#permalink]

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New post 05 Sep 2017, 21:43
Let the quantity of container 1 be x and container 2 be y
Then quantity of A in container 1 =5/6*X
Quantity of A in container 2= 1/4*x
Now we are given that the ratio of these two liquids in mixture is 1:1
Now we can set up the equation as
5/6*x +1/4*y =1/2(x+y)
20x+6y=24/2(x+y)
8x=6y
x/y=3/4
Hence D


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Re: Two liquids A and B are in the ratio 5:1 in container 1 and in the   [#permalink] 05 Sep 2017, 21:43
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Two liquids A and B are in the ratio 5:1 in container 1 and in the

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