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05 Aug 2021, 09:00
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C
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Difficulty:
25%
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Question Stats:
82% (02:03) correct
18%
(01:57)
wrong
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What is the greatest five-digit positive integer which when divided by 8, 9 and 10 leaves 3 as remainder in each case?
(A) 99,996
(B) 99,983
(C) 99,723
(D) 99,623
(E) 99,523
(A) 99,996
(B) 99,983
(C) 99,723
(D) 99,623
(E) 99,523
05 Aug 2021, 09:13
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LCM of those divisors is 360. Dividing 99999 by 360 leaves 279 as remainder. But we want 3 as remainder..
So substract 276 from 99999 which 99723 as the required number..
C is the answer.
Posted from my mobile device
So substract 276 from 99999 which 99723 as the required number..
C is the answer.
Posted from my mobile device
05 Aug 2021, 09:27
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use plug in
eliminate option A
among others
option C only passes the divisiblity test of 9 & 8
as sum of digits of 99720 = 9 divisible by 9
and 99720 is divisible by 2 thrice ; sufficient
option C is correct
eliminate option A
among others
option C only passes the divisiblity test of 9 & 8
as sum of digits of 99720 = 9 divisible by 9
and 99720 is divisible by 2 thrice ; sufficient
option C is correct
Bunuel
What is the greatest five-digit positive integer which when divided by 8, 9 and 10 leaves 3 as remainder in each case?
(A) 99,996
(B) 99,983
(C) 99,723
(D) 99,623
(E) 99,523
(A) 99,996
(B) 99,983
(C) 99,723
(D) 99,623
(E) 99,523
