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# What is the value of x if x is the remainder obtained when

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Manager
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What is the value of x if x is the remainder obtained when [#permalink]

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Updated on: 25 Mar 2011, 23:36
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63% (01:45) correct 37% (01:32) wrong based on 57 sessions

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What is the value of x if x is the remainder obtained when $$2^{8p+2} + Z$$is divided by 5 and p is a positive integer?

1) Z= 6
2) Z is even

Originally posted by dreambeliever on 25 Mar 2011, 20:19.
Last edited by dreambeliever on 25 Mar 2011, 23:36, edited 1 time in total.
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25 Mar 2011, 21:16
2(8p+2)+z
=16p+(z+4)

given:

16p + (z+4) = 5k + x

where k is a whole number

Statement 1:
Given: z = 6

If p = 1

16 + 10 = 26

26/5 leaves remainder 1

If p = 2
32 + 10 = 42
42/5 leaves remainder 2

Thus, insufficient!

Statement 2:
Z is even. So let z = 6
We already know that for z = 6, the statement is insufficient!
Therefore, statement 2 is also not sufficient.

Statement 1 & 2:
z = 6 obeys both the constraints imposed by Statement 1 & 2
But z = 6 does not yield a unique value of x

Therefore, insufficient!

ANS - 'E'
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25 Mar 2011, 23:35
dreambeliever wrote:
What is the value of x if x is the remainder obtained when $$2^(8p+2)$$+ Z is divided by 5 and p is a positive integer?

1) Z= 6
2) Z is even

Sorry corrected question stem.
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26 Mar 2011, 00:24
1
dreambeliever wrote:
What is the value of x if x is the remainder obtained when $$2^{8p+2} + Z$$is divided by 5 and p is a positive integer?

1) Z= 6
2) Z is even

$$2^{8p+2}$$

The unit digit of the above expression will always be 4.

Here's how;
$$2^n$$ has a cyclicity of 4. And the unit digits appear as 2,4,8,6 with every increment in n.

When "8p+2" is divided by 4, it always render a remainder of 2.
8p is divisible by 4 leaving the remainder as 0.
When 2 is divided by 4, it will leave a remainder of 2.

Whenever; in expression $$2^n$$, n divides by 4 and leaves a remainder of 2, the unit digit of the expression will be 4.

1. Z=6

4+6=0

The expression $$2^{8p+2} + Z$$ will always be divisible by 5 as the unit digit will always be 0. x=0;

Sufficient.

2. Z=even;

Z=2; The expression's units digit will be 6 and x=1;
Z=6; The expression's units digit will be 0 and x=0;

Not Sufficient.

Ans: "A"
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26 Mar 2011, 07:36
(2)^(8p+2) + Z

= (4)^(4p+1) + Z

4 raised to odd power ends with 4

So (4 +Z)/5 = x, x = ?

1) Z = 6, then x = 0

2) Insufficient as (4+2)/5 = Rem 1

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01 Apr 2011, 11:02
1. Z=6
8(p+2) = 2(4p+1)
hence 2 ^(8p+2) become 4^(4P+1)
any odd power to 4 gives 4 as the last digit
2 ^(8p+2) +Z = 4^(4P+1) +6 = <no with last digit as 0>
is divisible by 5. therefore remainder = 0

A or D

2. Z=even
<no with last digit as 4> +even will give different no.s for each value of Z
hence no fixed remainder

Therefore ans= A
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01 Apr 2011, 20:49
The answer should be A. Whatz the OA ?

obidan wrote:
1. Z=6
8(p+2) = 2(4p+1)
hence 2 ^(8p+2) become 4^(4P+1)
any odd power to 4 gives 4 as the last digit
2 ^(8p+2) +Z = 4^(4P+1) +6 = <no with last digit as 0>
is divisible by 5. therefore remainder = 0

A or D

2. Z=even
<no with last digit as 4> +even will give different no.s for each value of Z
hence no fixed remainder

Therefore ans= A
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17 Oct 2011, 14:20
Before the correction i thought its E..But yes IMO A
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Re: What is the value of x if x is the remainder obtained when [#permalink]

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23 Mar 2017, 05:48
Option A

Remainder of $$\frac{[2^{8p+2} + Z]}{5}$$

*To find remainder of any number when divided by 5, all we need to find is the remainder when unit's digit of that number is divided by 5*

$$2^{X}$$ has a cyclicity of 4, hence $$2^{8p+2}$$ will have the same unit's digit as $$2^{2}$$.

So unit's digit of $$2^{8p+2} = 4$$.

I: Z = 6
Now unit's digit of $$[2^{8p+2} + Z] = 4 + 6 = 10$$. Hence, remainder of $$\frac{[2^{8p+2} + Z]}{5}$$ = 0.
Sufficient.

II: Z = even. For every even number, unit's digit of $$[2^{8p+2} + Z]$$ will be different. Insufficient.
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Re: What is the value of x if x is the remainder obtained when   [#permalink] 23 Mar 2017, 05:48
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