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# When 3x^2 + nx + 5 = 0 has only one solution, n=?

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Manager
Joined: 28 May 2018
Posts: 87
Location: India
Schools: Tuck '21, ISB '20, NTU '20
GMAT 1: 640 Q45 V35
GMAT 2: 670 Q45 V37
When 3x^2 + nx + 5 = 0 has only one solution, n=?  [#permalink]

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17 Mar 2019, 10:54
2
00:00

Difficulty:

35% (medium)

Question Stats:

50% (01:01) correct 50% (02:19) wrong based on 16 sessions

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When $$3x^2 + nx + 5 = 0$$ has only one solution, n=?

A) $$\sqrt{48}$$
B) $$\sqrt{80}$$
C) $$10$$
D) $$3\sqrt{2}$$
E) $$\sqrt{60}$$

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Joined: 21 Feb 2019
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Re: When 3x^2 + nx + 5 = 0 has only one solution, n=?  [#permalink]

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17 Mar 2019, 11:00
1
If it has only one root, $$b^2 - 4ac = 0$$. Hence, $$n^2 - 4*3*5 = 0$$; $$n = \sqrt{60}$$.
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Re: When 3x^2 + nx + 5 = 0 has only one solution, n=?   [#permalink] 17 Mar 2019, 11:00
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# When 3x^2 + nx + 5 = 0 has only one solution, n=?

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