Bunuel wrote:
When all the boxes in a warehouse were arranged in stacks of 8, there were 4 boxes left over. If there were more than 80 but fewer than 120 boxes in the warehouse, how many boxes were there?
(1) If all the boxes in the warehouse had been arranged ins tacks of 9, there would have been no boxes left over.
(2) If all the boxes in the warehouse had been arranged in stacks of 12, there would have been no boxes left over
80 < n = 8a + 4 < 120, where a is a positive integer, so n = 84, 88, 92, 96, 100, 104, 108, 112, or 116.
We need to answer the question:
n = ?
Statement One Alone:=> If all the boxes in the warehouse had been arranged in stacks of 9, there would have been no boxes left over.
n = 9b, where b is a positive integer.
n must have been equal to 108, because 108 is the only possible value that is divisible by 9.
Statement one is sufficient. Eliminate answer choices B, C, and E.
Statement Two Alone:=> If all the boxes in the warehouse had been arranged in stacks of 12, there would have been no boxes left over.
n = 12c, where c is a positive integer.
n could have been equal to 84 or 108, because these possible values are divisible by 12.
Statement two is not sufficient.
Answer: ADear JeffTargetTestPrep, n can not be equal to 88, 96 and other multiples of 8 in the given range since in that case the "a" would not be an integer.