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Working independently X takes 12 hours to finish a certain

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VP
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Working independently X takes 12 hours to finish a certain [#permalink]

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New post 04 Nov 2008, 05:20
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Working independently X takes 12 hours to finish a certain work. he finishes 2/3 of the work . The rest of the work is finished by Y whose rate is 1/10 th of X. In how much time does Y finsh his work?
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Director
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Re: Simple work problem [#permalink]

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New post 04 Nov 2008, 05:30
Rate of X = 1/12 work/hr

Rate of Y = 1/120 work/hr

B has to do 1/3 of the work

1/3 = 1/120 * a

a= 40 hrs

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Re: Simple work problem [#permalink]

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New post 04 Nov 2008, 06:12
amitdgr wrote:
Working independently X takes 12 hours to finish a certain work. he finishes 2/3 of the work . The rest of the work is finished by Y whose rate is 1/10 th of X. In how much time does Y finsh his work?


X work 12 hrs.
Y work 12/10 hrs.

Work left 1/3
if Y work alone it takes 12/10 to finish
so Y work only 1/3 so it takes (12/10)*(1/3) = 4/10 hr

I don't know if my approach is correct, pls advice.

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Re: Simple work problem [#permalink]

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New post 04 Nov 2008, 06:55
I agree with Alpha , is the QA 40 hrs ?

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VP
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Re: Simple work problem [#permalink]

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New post 04 Nov 2008, 07:07
40 hrs is the answer
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Re: Simple work problem   [#permalink] 04 Nov 2008, 07:07
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