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Bunuel received 6 Kudos for post Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 0.

GiverPostDate
arpanghoshRe: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 006-Oct-2022
VakruRe: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 019-Dec-2019
shoaibkhRe: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 001-Sep-2019
IzzyjollyRe: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 025-Aug-2018
Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 024-May-2017
earnitRe: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 003-Oct-2014

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