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Bunuel received 7 Kudos for post If |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 0.

GiverPostDate
monkinaferrariIf |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 030-Oct-2022
Sanil98If |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 014-Oct-2022
aparnashah4348If |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 003-Oct-2022
ChehakguptaIf |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 030-Sep-2022
Sreshtha94If |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 029-Sep-2022
suyash1644If |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 018-Apr-2022
SelimAIUBIf |x| > 0, is x^y < 1? (1) x = 1/2 (2) y = 021-Mar-2022

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