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Kudos owned by the user


Izzyjolly received 4 Kudos for post Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 0.

GiverPostDate
Aryaa03Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 011-Jan-2024
Anjaneya324Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 002-Aug-2023
sathik63Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 026-Jan-2020
BunuelRe: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 026-Aug-2018

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