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ha15 received 31 Kudos for post # If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even.

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Luvlife# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even08-Oct-2020
deepshanker005# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even06-Oct-2020
Deepak502# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even04-Oct-2020
ngochuyen1904# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even30-Sep-2020
Pallavi1402# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even25-Sep-2020
Harsh123489# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even25-Sep-2020
fersal1994# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even07-Sep-2020
niharikaGup# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even27-Aug-2020
Ilmisrael# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even26-May-2020
pkochrollins# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even06-Apr-2020
Vsashvin# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even20-Feb-2020
JineshM# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even05-Feb-2020
RiaBatra# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even09-Nov-2019
Rohanborude# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even14-Oct-2019
CerCap# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even29-Jun-2019
NarlankaVijay# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even25-Jun-2019
Karanh1141# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even23-Jun-2019
clutchkingasiimov# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even22-Jun-2019
pthakoor# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even22-Jun-2019
kingboy2k3# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even29-May-2019
FlorenciaM# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even11-May-2019
janeyywang# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even07-Dec-2018
theshankman# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even24-Oct-2018
shmba# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even20-Aug-2018
ahonob# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even19-Aug-2018
ts3912# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even24-Jun-2018
Grapejam# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even18-Mar-2018
Blueblu# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even14-Nov-2017
Adityagmatclub# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even27-Jul-2017
varundixitmro2512# If a, b, c and d are integers, is (2^a·3^b)/(2^c·3^d) even11-Jul-2016

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