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mvictor received 2 Kudos for post Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 0.

GiverPostDate
Gmase88Re: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 022-Jan-2018
jpvemulaRe: Is x > y? (1) x + 2(xy)^(1/2) + y = 0 (2) x^2 - y^2 = 004-Mar-2016

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