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# (.0032)(.028)(100) / (.008)(.07)(50) =

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Senior Manager
Status: Studying GMAT
Joined: 04 Sep 2017
Posts: 281
Location: United States (UT)
GPA: 3.6
WE: Sales (Computer Software)

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10 Aug 2019, 14:18
2
1
00:00

Difficulty:

45% (medium)

Question Stats:

70% (01:47) correct 30% (01:33) wrong based on 138 sessions

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$$\frac{(.0032)(.028)(100)}{(.008)(.07)(50)}$$ =

(A) .16
(B) .32
(C) 3.2
(D) 32
(E) 64

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Joined: 20 Mar 2018
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10 Aug 2019, 16:19
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(.0032)(.028)(100)/(.008)(.07)(50)

=> (32/10^4)(28/10^3)(100)/ (8/10^3)(7/10^2)(50)
=>(32/10^4)(28/10^3)(2) • (10^3/8) (10^2/7)

=> (32•28•2/ 8•7) • (10^3•10^2/10^4•10^3)
(8•4)•(1/10^2) = 32/100 = 0.32

Or

(10^7/10^7)(.0032)(.028)(100)/(.008)(.07)(50)
=> (32)(28)(100)/(80)(70)(50)
=> (4)(4)(2)/(100) =0.32

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Senior Manager
Status: Studying GMAT
Joined: 04 Sep 2017
Posts: 281
Location: United States (UT)
GPA: 3.6
WE: Sales (Computer Software)

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11 Aug 2019, 10:03
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1
MikeScarn wrote:
$$\frac{(.0032)(.028)(100)}{(.008)(.07)(50)}$$ =

(A) .16
(B) .32
(C) 3.2
(D) 32
(E) 64

I think the easiest way is to look at this as 3 separate fractions.

For each fraction, move the denominator over to right in order to get whole numbers.

$$\frac{.0032}{0.008}$$ --> $$\frac{32}{80}$$ --> $$\frac{4}{10}$$

$$\frac{0.028}{0.07}$$ --> $$\frac{28}{70}$$ --> $$\frac{4}{10}$$

$$\frac{100}{50}$$ --> $$\frac{2}{1}$$

$$\frac{4}{10}$$ * $$\frac{4}{10}$$ * $$\frac{2}{1}$$ = $$\frac{32}{100}$$ = .32
_________________
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Joined: 13 Apr 2020
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21 May 2020, 11:31
Another method: use scientific notation to group the decimals together. Rewrite each number as $$x*10^y$$, where x is an integer. Group the powers of 10 together to keep track of them, and perform standard division/multiplication of the integers.

$$.0032=32*10^{-4}$$
$$.028=28*10^{-3}$$
$$\frac{100}{50} = 2$$
$$.008 = 8*10^{-3}$$
$$.07=7*10^{-2}$$

Now rewrite it and group the powers of 10 together.
So now the numerator is: $$(32*10^{-4})*(28*10^{-3})*(2)=(10^{-7})*(32)*(28)*(2)$$
and the denominator is : $$(8*10^{-3})*(7*10^{-2})=(10^{-5})*(8)*(7)$$

Combine the powers of 10 and simplify by dividing, the entire equation is:
$$\frac{(10^{-7})*(32)*(28)*(2)}{(10^{-5})*(8)*(7)}=(10^{-2})*(4)*(4)*(2)=\frac{32}{10^{2}}=\frac{32}{100}=.32$$
(.0032)(.028)(100) / (.008)(.07)(50) =   [#permalink] 21 May 2020, 11:31