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(.08)^(-4)/(.04)^(-3) =

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pmklings
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(.08)^(-4)/(.04)^(-3) = [#permalink] New post   Updated on: 09 Aug 2016, 01:59
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Question Stats:

77% (01:57) correct 23% (02:25) wrong based on 341 sessions
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\(\frac{(.08)^{-4}}{(.04)^{-3}} =\)

(A) -16/25
(B) 16/25
(C) 25/16
(D) 16
(E) 25
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Official Answer
C

Originally posted by pmklings on 18 Sep 2015, 19:13.
Last edited by Bunuel on 09 Aug 2016, 01:59, edited 2 times in total.
Renamed the topic and edited the question.
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goathoof
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink] New post   29 Apr 2016, 13:54
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\(\frac{(.08)^{-4}}{(.04)^{-3}} =\)

(A) -16/25
(B) 16/25
(C) 25/16
(D) 16
(E) 25
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink] New post   18 Sep 2015, 20:46
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(.08)^-4/(.04)^-3 can be written as
\((8*10^{-2})^{-4}/(4*10^{-2})^{-3} = (2^{-12}*10^{8})/(2^{-6}*10^{6}) = 100/2^{6} = 25/16\)

Option C
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deabas
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink] New post   29 Apr 2016, 14:31
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Ok.. Let's start by turning the exponents into positive ones

(.08)^-4/(.04)^-3 = (.04)^3/(.08)^4

Notice that: (.04)^3 = (4/100)^3 = 4^3/100^3
also (.08)^4 = (8/100)^4 = 8^4/100^4

So the expression becomes: 4^3*100^4/8^4*100^3 = (2^2)^3*100/(2^3)^4 = 2^6*100/2^12 = 100/2^6 = 2^2*5^2/2^6 = 5^2/2^4 = 25/16

The answer is "C"

Gooood luck!
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink] New post   08 Aug 2016, 11:32
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Konstantin1983 wrote:
What am i doing wrong?

(0.08)=2*0.04 Hence we can write this expression as 2((0.04)^-4)/(0.04^-3) Since we have division here we can write this as (0.04^-1) right? Hence we have 2*(100/4)=50 What is wrong? Please help?


The numerator is (0.08)^-3, so if you take 2 as common, you need to include the power to 2 as well.

As in, (p*q)^n = p^n * q^n
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Konstantin1983
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink] New post   08 Aug 2016, 10:56
What am i doing wrong?

(0.08)=2*0.04 Hence we can write this expression as 2((0.04)^-4)/(0.04^-3) Since we have division here we can write this as (0.04^-1) right? Hence we have 2*(100/4)=50 What is wrong? Please help?
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Konstantin1983
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink] New post   09 Aug 2016, 15:00
abhimahna wrote:
Konstantin1983 wrote:
What am i doing wrong?

(0.08)=2*0.04 Hence we can write this expression as 2((0.04)^-4)/(0.04^-3) Since we have division here we can write this as (0.04^-1) right? Hence we have 2*(100/4)=50 What is wrong? Please help?


The numerator is (0.08)^-3, so if you take 2 as common, you need to include the power to 2 as well.

As in, (p*q)^n = p^n * q^n


Oh yeah right Abhimahna) Stupid mistake!
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink] New post   14 Sep 2023, 18:30
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Re: (.08)^(-4)/(.04)^(-3) = [#permalink]
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