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# (1-1/2)^2 ( 1-1/3)^2=

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Math Expert
Joined: 02 Sep 2009
Posts: 58464

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24 Feb 2019, 23:56
00:00

Difficulty:

15% (low)

Question Stats:

91% (00:39) correct 9% (01:04) wrong based on 32 sessions

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$$(1-\frac{1}{2})^2 ( 1-\frac{1}{3})^2=$$

A. $$\frac{25}{36}$$

B. $$\frac{1}{3}$$

C. $$\frac{1}{6}$$

D. $$\frac{1}{9}$$

E. $$\frac{1}{18}$$

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Joined: 18 Aug 2017
Posts: 5043
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)

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25 Feb 2019, 01:25
Bunuel wrote:
$$(1-\frac{1}{2})^2 ( 1-\frac{1}{3})^2=$$

A. $$\frac{25}{36}$$

B. $$\frac{1}{3}$$

C. $$\frac{1}{6}$$

D. $$\frac{1}{9}$$

E. $$\frac{1}{18}$$

solve for expression
we get
$$\frac{1}{9}$$

IMO D
VP
Joined: 31 Oct 2013
Posts: 1468
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)

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25 Feb 2019, 01:48
Bunuel wrote:
$$(1-\frac{1}{2})^2 ( 1-\frac{1}{3})^2=$$

A. $$\frac{25}{36}$$

B. $$\frac{1}{3}$$

C. $$\frac{1}{6}$$

D. $$\frac{1}{9}$$

E. $$\frac{1}{18}$$

$$(1-\frac{1}{2})^2 ( 1-\frac{1}{3})^2$$

$$(1/2)^2 (2/3)^2$$

1/4 * 4/9

1/9.

Re: (1-1/2)^2 ( 1-1/3)^2=   [#permalink] 25 Feb 2019, 01:48
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