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(3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ?

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(3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ?  [#permalink]

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New post 12 May 2016, 00:45
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A
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(3x + 2) (2x - 5) = ax^2 + kx + n . What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11
Spoiler: OA

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Re: (3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ?  [#permalink]

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New post 12 May 2016, 07:04
Bunuel wrote:
(3x + 2) (2x - 5) = ax^2 + kx + n . What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11


Simplify LHS..
\((3x+2)(2x-5) = 6x^2-11x-10 = ax^2-n+k\)...
equate the coefficients...
a=6 ; k = -11 and n = -10..
so \(a-n+k = 6-(-10)+(-11) = 6+10-11 = 5\)
A
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Re: (3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ?  [#permalink]

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New post 13 May 2016, 00:13
1
Bunuel wrote:
(3x + 2) (2x - 5) = ax^2 + kx + n . What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11


Expanding we have 6x^2 - 15x + 4x -10
6x^2 - 11x - 10

Taking coefficients, a = 6, k= -11, n = -10

Therefore a - n + k = 6 - (-10) - 11 = 16 - 11 = 5

The answer is A.
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Re: (3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ?  [#permalink]

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Re: (3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ?   [#permalink] 02 Feb 2019, 17:47
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