A certain ball team has an equal number of right- and left-h

Firstly choose and value keeping fractions in mind.

Let us take value of total no. players be 180

As there are equal no. of left hand players and no. of right hand players ,
therefore left players = right players = 90

-----> no. of players absent on the practice day = \(\frac{2}{3} * 180 = 120\)

no. of players present on the practice day = \(180-120 = 60\)

----> no. of left hand players present on the practice day = \(\frac{1}{3} * 60 = 20\)

therfore no. of left hand players absent on the practice day = \(90-20 = 70\)

-----> no. of right hand players present on the practice day = \(\frac{2}{3} * 60 = 40\)

therefore, no. of right hand players absent on the practice day = \(90-40 = 50\)

no. of right hand players absent on the practice day = \(\frac{50}{70} = \frac{5}{7}\)
no. of left hand players absent on the practice day


therfore answer is C

1. Say total students = 90

2. Total Left Handed would be = 45

3. Total Right Handed would be = 45

4. Total absent are \(\frac{2}{3}\) rd = 60

5. Total present would be = 30

6. \(\frac{1}{3}\) rd of present are Left Handed \(= \frac{30}{3} = 10\)

7. Absent Left Handed are = 45-10 = 35

8. Present Right Handed would be = 30-10 = 20

9. Absent right handed would be = 45-20 = 25

Required ratio\(= \frac{25}{35} = \frac{5}{7}\)

Answer = C

We can let the number of right- and left-handed players be 9 (we are using the number 9 because it’s a multiple of 3). Thus, there are a total of 18 players on the team.

Since we are given that on certain day, ⅔ of the players were absent, 12 players were absent and 6 players were present. Of the 6 players who were present, ⅓ were left-handed, so 2 players were left-handed and 4 players were right-handed.

Since we’ve assumed there were 9 right-handed players and 9 left-handed players on the team, 5 right-handed players were absent and 7 left-handed players were absent. So, the ratio of absent right-handed players to absent left-handed players is 5 to 7.

Answer: C

I seem to have an issue picking the right SMART numbers.

For example, I had started out with the total number of players as 60 then 12. How do you preemptively pick an easy number given the 1/3 and 2/3 calculations?

Thanks!

Hi

It helps to consider the fractions as the question runs along. While reading I jotted down: 1/2 , 2/3 , and finally 1/3. The product being 2/18. Therefore, picking 18 is likely to be a good start.

Hope that helps.

Cheers

Wow. So simple, yet totally didn't cross my mind to just multiply the "given" fractions. Thank you!

[
I kind of picked 30 as my total students. So RH =LH=15. Got the final ratio as 2/3. Although it's not the correct answer, could you point the mistake I made here.

PS: This is how I solved the problem.
Students absent for practice=2/3(30)=20.
Students present =10

LH students present =1/3(10) ~3. So RH students=7.

Hence final ratio=(15-7)/(15-3)=8/12 ==2/3
]