sivasanjeev wrote:

A certain ball team has an equal number of right- and left-handed players. On a certain day, two-thirds of the players were absent from practice. Of the players at practice that day, one-third were left handed. What is the ratio of the number of right-handed players who were not at practice that day to the number of lefthanded players who were not at practice?

A. 1/3

B. 2/3

C. 5/7

D. 7/5

E. 3/2

We can let the number of right- and left-handed players be 9 (we are using the number 9 because it’s a multiple of 3). Thus, there are a total of 18 players on the team.

Since we are given that on certain day, ⅔ of the players were absent, 12 players were absent and 6 players were present. Of the 6 players who were present, ⅓ were left-handed, so 2 players were left-handed and 4 players were right-handed.

Since we’ve assumed there were 9 right-handed players and 9 left-handed players on the team, 5 right-handed players were absent and 7 left-handed players were absent. So, the ratio of absent right-handed players to absent left-handed players is 5 to 7.

Answer: C

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