A certain electrolyte solution contains 1 gram of salt for every 8 gra

given
salt:sugar:water
1:8:200
sugar/water = 8/200 * 1/2 ; 1/50
salt/sugar ; 1/8 * 3 ; 3/8
3x/8= 5
x= 40/3
sugar ; 40*50/3 = 2000/3 IMO C ; 666 2/3

When "the salt ratio is trippled" why do we get 3/8 instead of 1/24?

Similarly with halving the sugar to water ratio. Why sis you get 1/50 instead of 8/100?

Best

Hi GloryBoy92,

Lets say we have a number 3 , now we want to triple it or increase it. What do we do ? We multiply don't we? We do 3*3 to get 9
Now lets say we want to decease the same number to half its value, what do we do , we divide by 2 don't we hence we have \(\frac{3}{2}\)
Now lets says we wanted to make the same number even smaller or reduce to \(\frac{1}{3}\) of its value , what do we do ? we divide by 3 don't we, to get \(\frac{3}{3}\)=1

Hence to increase a number ( Ratio in this case ) we have to multiply and to decrease a number ( Ratio in this case)we
have to divide.

Similarly Sugar to water ratio is \(\frac{8}{200}\)we want to make it half or decrease it hence as shown above we have to divide by 2 to get \(\frac{8}{400}\) which when reduced gives \(\frac{1}{50}\)
What you are doing is multiplying \(\frac{8}{200}\)*2 = \(\frac{8}{100}\) but this operation is increasing the number instead of decreasing it.
In the same way we have a number \(\frac{1}{8}\) now we want to triple it or increase it , What do we do? like the first case above we multiply by 3 don't we? hence we do \(\frac{1}{8}\)*3 to get \(\frac{3}{8}\)
If we wanted to decrease \(\frac{1}{8}\) to \(\frac{1}{3}\) of its value then we needed to divide \(\frac{1}{8}\) by 3 to get \(\frac{1}{24}\).This is what you were doing.

Hope this answer's your question, please fee free to ask if anything is still unclear.Thanks.

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