A certain jar contains 20 jellybeans; each jellybean is either black,

Solution

Step 1: Analyse Question Stem

• Let us assume that b, p, and y are the number of black, pink and yellow jellybeans in the jar, respectively.

o \(b + p + y = 20 …………..Eq.(i)\)
• We need to find out if p > y

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE

• \(b > p\)
• We have no information about y. so we cannot find if p > y. For example:

o Case 1: b can be 10, p can be 6 and y can be 4, such that \(b + p + y = 20\) and \(b > p\)

 In this case, \(p > y\)
o Case 2: However, b can be 10, p can be 4 and y can be 6, such that \(b + p + y = 20\) and \(b > p\)

 In this case \(p < y\)
• We are getting contradictory results.

• According to this statement: \(p = 6\)
• However, this statement gives no information about b and y.

Step 3: Analyse Statements by combining.

• \(b > p\) and \(p = 6\)
• So, from above and equation (i), we can write,

o \(y = 20 – b – p ⟹ y < 20 – 6 – 6 ⟹ y < 8\)
o Therefore, y can be 7, in that case p < y

 Also, y can be 5, in that case p > y
• We are still getting contradictory results.