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Re: A certain rectangle has an area of 48 and a perimeter of 32. What is [#permalink]
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bhavik29 wrote:
Sorry how is the answer E?


The OA is D. Edited. Thank you for noticing!
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Re: A certain rectangle has an area of 48 and a perimeter of 32. What is [#permalink]
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Bunuel wrote:
A certain rectangle has an area of 48 and a perimeter of 32. What is the length of the diagonal of the rectangle?

A. 4
B. \(4\sqrt{3}\)
C. 16
D. \(4\sqrt{10}\)
E. 160


We can create the equations where L = Length and W = Width.
LW = 48

And

2L + 2W = 32

L + W = 16

If we square L + W = 16, we have:

L^2 + W^2 + 2LW = 16^2

L^2 + W^2 + 2LW = 256

Since LW = 48, we have:

L^2 + W^2 + 96 = 256

L^2 + W^2 = 160

Lastly, since diagonal^2 = L^2 + W^2, we have:

160 = D^2

√16 x √10 = D

4√10 = D

Answer: D
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Re: A certain rectangle has an area of 48 and a perimeter of 32. What is [#permalink]
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