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A certain restaurant offers 8 different salads, 5 different main cours
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26 Feb 2015, 05:38
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A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
Re: A certain restaurant offers 8 different salads, 5 different main cours
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28 Feb 2015, 03:52
Bunuel wrote:
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
A. 120 B. 240 C. 480 D. 600 E. 1200
Kudos for a correct solution.
One salad can be chosen in 8C1 = 8 ways One main course can be chosen in 5C1 = 5 ways Two desserts can be chosen in 6C2 = 15 ways
Total number of ways = 8*5*15 = 600 Hence option D.
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Re: A certain restaurant offers 8 different salads, 5 different main cours
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02 Mar 2015, 05:18
Bunuel wrote:
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
To count the number of meals, we have to count the possibilities for the three components, and then, according to the Fundamental Counting Principle, we multiply. For more on the FCP, see this blog.
For salads, there are 8 possibilities. Done.
For main courses, there are 5 different possibilities. Done.
For desserts, there are 6 choices, but we pick two different choices. This would be 6C2. To calculate this, we can use the shortcut, nC2 = (n*(n-1))/2.
6C2 = (6*5)/2 = 15
So, there are 15 combinations of two different desserts.
For the number of meals, we multiply 8*5*15. We know 8*5 = 40. Then, we need 40*15. Well, 4*15 = 60, so 40*15 must be 600.
Re: A certain restaurant offers 8 different salads, 5 different main cours
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25 Mar 2016, 12:17
Salad can be choosen in 8C1 ways Main Course can be choosen in 5C1 ways Desserts can be choosen in 6C2 ways Therefore answer will be product which is as follows 8C1*5C1*6C2=8*5*15=600
Re: A certain restaurant offers 8 different salads, 5 different main cours
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20 Apr 2018, 05:31
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Bunuel wrote:
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
A. 120 B. 240 C. 480 D. 600 E. 1200
Kudos for a correct solution.
Take the task of creating a meal and break it into stages.
Stage 1: Select 1 salad There are 8 different salads from which to choose, so we can complete stage 1 in 8 ways
Stage 2: Select 1 main course There are 5 different main courses from which to choose, so we can complete stage 2 in 5 ways
Stage 3: Select 2 different desserts Since the order in which we select the desserts does not matter, we can use combinations. We can select 2 desserts from 6 desserts in 6C2 ways (15 ways) So, we can complete stage 3 in 15 ways
By the Fundamental Counting Principle (FCP), we can complete all 3 stages (and thus create a meal) in (8)(5)(15) ways (= 600 ways)
Answer: D
Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. So, be sure to learn it.
Re: A certain restaurant offers 8 different salads, 5 different main cours
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23 Apr 2018, 16:41
Bunuel wrote:
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
A. 120 B. 240 C. 480 D. 600 E. 1200
The number of meals is:
8C1 x 5C1 x 6C2 = 8 x 5 x (6 x 5)/2! = 8 x 5 x 15 = 600
Re: A certain restaurant offers 8 different salads, 5 different main cours
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17 Feb 2020, 15:42
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