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8c1 * 5c1 * 6c2 = 8*5*15 = 600

Answer D
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Bunuel
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?

A. 120
B. 240
C. 480
D. 600
E. 1200

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One salad can be chosen in 8C1 = 8 ways
One main course can be chosen in 5C1 = 5 ways
Two desserts can be chosen in 6C2 = 15 ways

Total number of ways = 8*5*15 = 600
Hence option D.

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Bunuel
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?

A. 120
B. 240
C. 480
D. 600
E. 1200

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MAGOOSH OFFICIAL SOLUTION:

To count the number of meals, we have to count the possibilities for the three components, and then, according to the Fundamental Counting Principle, we multiply. For more on the FCP, see this blog.

For salads, there are 8 possibilities. Done.

For main courses, there are 5 different possibilities. Done.

For desserts, there are 6 choices, but we pick two different choices. This would be 6C2. To calculate this, we can use the shortcut, nC2 = (n*(n-1))/2.

6C2 = (6*5)/2 = 15

So, there are 15 combinations of two different desserts.

For the number of meals, we multiply 8*5*15. We know 8*5 = 40. Then, we need 40*15. Well, 4*15 = 60, so 40*15 must be 600.

Answer = (D)
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Salad can be choosen in 8C1 ways
Main Course can be choosen in 5C1 ways
Desserts can be choosen in 6C2 ways
Therefore answer will be product which is as follows
8C1*5C1*6C2=8*5*15=600

Hence Answer-D
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Bunuel
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?

A. 120
B. 240
C. 480
D. 600
E. 1200

The number of meals is:

8C1 x 5C1 x 6C2 = 8 x 5 x (6 x 5)/2! = 8 x 5 x 15 = 600

Answer: D
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