Bunuel
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
A. 120
B. 240
C. 480
D. 600
E. 1200
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:To count the number of meals, we have to count the possibilities for the three components, and then, according to the
Fundamental Counting Principle, we multiply. For more on the FCP, see
this blog.
For salads, there are 8 possibilities. Done.
For main courses, there are 5 different possibilities. Done.
For desserts, there are 6 choices, but we pick two different choices. This would be 6C2. To calculate this, we can use
the shortcut, nC2 = (n*(n-1))/2.
6C2 = (6*5)/2 = 15
So, there are 15 combinations of two different desserts.
For the number of meals, we multiply 8*5*15. We know 8*5 = 40. Then, we need 40*15. Well, 4*15 = 60, so 40*15 must be 600.
Answer = (D)