A convenience store currently stocks 48 bottles of mineral water.
The bottles have two sizes of either 20 or 40 ounces each. The average
volume per bottle the store currently has in stock is 35 ounces. How many 40
ounce bottles must be sold for the average volume per bottle to be reduced to 25
ounces if no 20 ounce bottles are sold?
Hi,
the other method would be weighted average method.. people have already used it above, still ill do it once again..
TWO steps..
first - initial numbers20 and 40 avail and average is 35..
so \(\frac{# of 20}{# of 40} = \frac{40-35}{35-20} = \frac{1}{3}\)
so # of 20 \(= \frac{1}{1+3} *48 =12\)..
and # of 40 ounces = 48-12 = 36
second - 20 and 40 avail and average is 25..
so\(\frac{# of 20}{# of 40} = \frac{40-25}{25-20} =\frac{3}{1}\)
so # of 20\(= \frac{3}{1+3} *x =12\),
here we know # of 20 ounces remains constant..so x= 16
and # of 40 ounces = 16-12 = 4..
now # of 40 ounces bottle sold = 36-4 = 32
question stem says:if no 20 ounce bottles are sold, meaning no bottles are sold at all , not : additional bottles are not sold.
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