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why is 3 incorrect? If there are 2(Block dots) and 1(Red dot) does this mean we can have 0(Green dots) ?
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My line of reasoning for this question is that the total number of dots must be odd. That leaves me with options A & D, but since 3 seems unlikely ("exactly two black dots and exactly one green dot for every two red dots"), I chose to go with D. Can someone confirm if my process made logical sense?
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priyankagh
My line of reasoning for this question is that the total number of dots must be odd. That leaves me with options A & D, but since 3 seems unlikely ("exactly two black dots and exactly one green dot for every two red dots"), I chose to go with D. Can someone confirm if my process made logical sense?

No, that's not right -- we might have 4 black, 2 green and 4 red dots here, for example, for a total of 10 dots, which is even.

Regor60 above posted the correct solution: for every 1 green dot we have 2 red dots and 2 black dots. So we can divide all the dots into sets of 5, where each set has 1 green, 2 red and 2 black dots. So the total number of dots must be a multiple of 5 (and it could be any positive multiple of 5 at all, but of the answer choices, only 45 is possible).
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