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# A gear 50 inches in diameter turns a smaller gear 30 inches in diamet

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Math Expert
Joined: 02 Sep 2009
Posts: 51100
A gear 50 inches in diameter turns a smaller gear 30 inches in diamet  [#permalink]

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26 Feb 2018, 22:22
00:00

Difficulty:

25% (medium)

Question Stats:

74% (01:14) correct 26% (01:15) wrong based on 40 sessions

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A gear 50 inches in diameter turns a smaller gear 30 inches in diameter. If the larger gear makes 15 revolutions, how many revolutions does the smaller gear make in that time?

(A) 9

(B) 12

(C) 20

(D) 25

(E) 30

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A gear 50 inches in diameter turns a smaller gear 30 inches in diamet  [#permalink]

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26 Feb 2018, 22:36
1
Bunuel wrote:
A gear 50 inches in diameter turns a smaller gear 30 inches in diameter. If the larger gear makes 15 revolutions, how many revolutions does the smaller gear make in that time?

(A) 9

(B) 12

(C) 20

(D) 25

(E) 30

If the gear with diameter 50 inches makes 15 revolutions,

then the smaller gear(diameter: 30 inches) makes $$\frac{50}{30} * 15 = 25$$ revolutions

Therefore, the smaller gear will make 25 revolutions n the same time(Option D)
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A gear 50 inches in diameter turns a smaller gear 30 inches in diamet  [#permalink]

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27 Feb 2018, 21:53
1
Bunuel wrote:
A gear 50 inches in diameter turns a smaller gear 30 inches in diameter. If the larger gear makes 15 revolutions, how many revolutions does the smaller gear make in that time?

(A) 9

(B) 12

(C) 20

(D) 25

(E) 30

IMO D circumference of circle is 2pie r and we have diameter than pie d
now we will find total distance covered in 15 revolution
so 15*50pie is total distance covered now we need to divide it by 30pie circumference of smaller circle as we need to find revolutions
15*50 pie/30pie= 25
If you like my explanation then please give me KUDOS
A gear 50 inches in diameter turns a smaller gear 30 inches in diamet &nbs [#permalink] 27 Feb 2018, 21:53
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