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A line passes through (1,p), is its slope greater than 0? [#permalink]
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Bunuel wrote:
gmatophobia wrote:
Bunuel wrote:
A line passes through (1,p), is its slope greater than 0?

(1) The line passes through (p,13)
(2) The line passes through (p,-1)


Statement 1

(1) The line passes through (p,13)

Slope =\(\frac{ y_2 - y_1 }{ x_2 - x_1}\) = \(\frac{13 - p }{ p - 1}\)

For certain values of p, the slope is greater than 0. For p = 13, the slope = 0

The statement is not sufficient.

Statement 2

(2) The line passes through (p,-1)

Slope =\(\frac{ y_2 - y_1 }{ x_2 - x_1}\) = \(\frac{ -1-p }{ p - 1}\)

For certain values of p, the slope is greater than 0. For p = -1, the slope = 0

The statement is not sufficient.

Combined

The statements combined

\(\frac{ -1-p }{ p - 1}\) = \(\frac{13 - p }{ p - 1}\)

Solving we can get an unique value of p. Sufficient.

Option C


And what would that solution be? Is the slope greater than 0?


(p-1)(-1-p) = (p-1)(13-p)

(p-1)[-1-p -13 +p] = 0

(p-1) * -14 = 0

p = 1

The slope is undefined.

In fact we can see this behavior using the statements as well. For the same value of p (i.e. x coordinate), the line has two different values of y coordinate. Hence the line is parallel to Y axis.
GMAT Club Bot
A line passes through (1,p), is its slope greater than 0? [#permalink]
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