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A lock code was product of two numbers, one taken from set A GMAT
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25 Dec 2018, 00:01
Question Stats:
66% (02:08) correct 34% (02:04) wrong based on 68 sessions
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A lock code was product of two numbers, one taken from set A = {2, 3, 4, 5, 9} and other taken from set B = {1, 2, 6, 7}. If all possible combinations of numbers from set A and set B are checked, what is the probability of opening the lock if entering any multiple of 6 will open the lock? a) 1/7 b) 3/5 c) 1/2 d) 3/10 e) 7/20
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Re: A lock code was product of two numbers, one taken from set A GMAT
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25 Dec 2018, 00:18
Nikhitaarorah wrote: A lock code was product of two numbers, one taken from set A = {2, 3, 4, 5, 9} and other taken from set B = {1, 2, 6, 7}. If all possible combinations of numbers from set A and set B are checked, what is the probability of opening the lock if entering any multiple of 6 will open the lock?
a) 1/7 b) 3/5 c) 1/2 d) 3/10 e) 7/20 So total combinations possible = 20 (5 items of A multiplied by 4 items of B) Combinations opening the locks must be multiple of 6, so they must be either 6,12,18,24,30,36 and so on so combinations possible from given set: 2X6, 3X2, 3X6, 4X6, 5X6, 9X6,9X2, so a total of 7 combinations, Answer is 7/20 E
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Re: A lock code was product of two numbers, one taken from set A GMAT
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28 Dec 2018, 11:37
Total cases : 5C1*4C1=20 & possible +ve combinations =7 [ (2,6),(3,2),(3,6),(4,6),(5,6),(9,2),(9,6),] Hence probability= 7/20 ....... Ans E
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A lock code was product of two numbers, one taken from set A GMAT
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28 Dec 2018, 12:12
Nikhitaarorah wrote: A lock code was product of two numbers, one taken from set A = {2, 3, 4, 5, 9} and other taken from set B = {1, 2, 6, 7}. If all possible combinations of numbers from set A and set B are checked, what is the probability of opening the lock if entering any multiple of 6 will open the lock?
a) 1/7 b) 3/5 c) 1/2 d) 3/10 e) 7/20 the number of possible combinations = 5 elements of A * 4 elements of B = 20 product outcomes favorable outcomes which are multiples of 6 are (2*6=12), (3*2=6), (3*6=18), (4*6=24), (5*6=30), (9*2=18), (9*6=54) .. so only 7 outcomes the probability of opening the lock = 7/20 which is E
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Re: A lock code was a product of 2 numbers, one taken from set A= {2,3,4,5
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12 Feb 2019, 11:59
Total.no of combinations =20 Total no. Of possible conbinations =(2,3)(2,9)(6,2)(6,3)(6,4)(6,5)(6,9)
Thus 7/20, e is the correct option
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Re: A lock code was a product of 2 numbers, one taken from set A= {2,3,4,5
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12 Feb 2019, 14:10
akurathi12 wrote: A lock code was a product of 2 numbers, one taken from set A= {2,3,4,5,9} and other taken from set B={1,2,6,7}. If all possible combinations of numbers from set A and set B are checked, what is the probability of opening the lock if entering any multiple of 6 will open the lock?
A. 1/7 B. 3/5 C. 1/2 D. 3/10 E. 7/20 Set A has 5 numbers Set B has 4 numbers Total number of combinations = 5*4 = 20 Preferred Outcomes = all multiples of 6 => Let's see the number of combinations wrt set B 1 > None of the numbers form multiples of 6 2 > 3 & 9 are eligible 6 > All 5 numbers are eligible 7 > None are eligible => Preferred outcomes = 7 Probability = Preferred/Total Outcomes = 7/20 Hence E is the correct answer.
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Re: A lock code was a product of 2 numbers, one taken from set A= {2,3,4,5
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