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A motorcycle messenger leaves his home base and travels at 40 miles an

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Bunuel
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A motorcycle messenger leaves his home base and travels at 40 miles an [#permalink] New post   28 Mar 2017, 02:50
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A motorcycle messenger leaves his home base and travels at 40 miles an hour to make a delivery 20 miles away. If the messenger wishes to be back at his home base 50 minutes after he left it, then how fast must he travel on his return trip?

A. 24 miles per hour
B. 45 miles per hour
C. 60 miles per hour
D. 90 miles per hour
E. 120 miles per hour
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C
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mohshu
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Re: A motorcycle messenger leaves his home base and travels at 40 miles an [#permalink] New post   28 Mar 2017, 03:06
he travels 20 miles at 40 mph so,, time consumed = 30 mins..
on his way back he has 20 mins left, so he should travel by 60 mph on his way back

Ans C
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Re: A motorcycle messenger leaves his home base and travels at 40 miles an [#permalink] New post   28 Mar 2017, 03:31
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Bunuel wrote:
A motorcycle messenger leaves his home base and travels at 40 miles an hour to make a delivery 20 miles away. If the messenger wishes to be back at his home base 50 minutes after he left it, then how fast must he travel on his return trip?

A. 24 miles per hour
B. 45 miles per hour
D. 60 miles per hour
D. 90 miles per hour
E. 120 miles per hour


Bunuel : just a minor correction (highlighted part). It should be C instead of D.

initial speed = 40 mph
distance = 20 m

time taken = 20/40 = 1/2 hour = 30 mins

time remaining = 50-30 =20 mins = 1/3 hour

new speed = 20/(1/3) = 60 mph

Hence option C is correct
Hit Kudos if you liked it 8-)
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Bunuel
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Re: A motorcycle messenger leaves his home base and travels at 40 miles an [#permalink] New post   28 Mar 2017, 03:33
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0akshay0 wrote:
Bunuel wrote:
A motorcycle messenger leaves his home base and travels at 40 miles an hour to make a delivery 20 miles away. If the messenger wishes to be back at his home base 50 minutes after he left it, then how fast must he travel on his return trip?

A. 24 miles per hour
B. 45 miles per hour
D. 60 miles per hour
D. 90 miles per hour
E. 120 miles per hour


Bunuel : just a minor correction (highlighted part). It should be C instead of D.

initial speed = 40 mph
distance = 20 m

time taken = 20/40 = 1/2 hour = 30 mins

time remaining = 50-30 =20 mins = 1/3 hour

new speed = 20/(1/3) = 60 mph

Hence option C is correct
Hit Kudos if you liked it 8-)


Typo edited. Thank you.
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Re: A motorcycle messenger leaves his home base and travels at 40 miles an [#permalink] New post   30 Mar 2017, 16:41
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Bunuel wrote:
A motorcycle messenger leaves his home base and travels at 40 miles an hour to make a delivery 20 miles away. If the messenger wishes to be back at his home base 50 minutes after he left it, then how fast must he travel on his return trip?

A. 24 miles per hour
B. 45 miles per hour
C. 60 miles per hour
D. 90 miles per hour
E. 120 miles per hour


Since the messenger is traveling at a rate of 40 mph and delivers a package 20 miles away, it takes him 20/40 = 1/2 an hour, or 30 minutes, to deliver the package. Since he needs to return home in 50 minutes and he has used 30 minutes, he has 20 minutes, or 1/3 of an hour, to get back home. Since rate = distance/time, his rate on his return trip is:

rate = 20/(1/3) = 20 x 3 = 60 mph

Answer: C
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A motorcycle messenger leaves his home base and travels at 40 miles an [#permalink] New post   26 Apr 2017, 14:03
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A good question to drive home the imperative "READ CAREFULLY." I missed "after he left [homebase]" and calculated the rate it would take him to go 20 miles in 50 minutes.:-(
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A motorcycle messenger leaves his home base and travels at 40 miles an [#permalink]
26 Apr 2017, 14:03
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