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Re: A parking lot contains ten cars. The average age of the cars is seven [#permalink]
Bunuel wrote:
A parking lot contains ten cars. The average age of the cars is seven years. If the average age of nine of the cars is six years, what is the age of the remaining car in years?

(A) 3
(B) 7
(C) 10
(D) 16
(E) 20

\(10*7 - 6*9\)

= \(70 - 54\)

= 16, Answer must be \((D) 16\)
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Re: A parking lot contains ten cars. The average age of the cars is seven [#permalink]
Expert Reply
Bunuel wrote:
A parking lot contains ten cars. The average age of the cars is seven years. If the average age of nine of the cars is six years, what is the age of the remaining car in years?

(A) 3
(B) 7
(C) 10
(D) 16
(E) 20



The total sum of the ages of all 10 cars is 10 x 7 = 70.

The sum of the 9 cars is 9 x 6 = 54

Therefore, the age of the remaining car is 70 - 54 = 16.

Answer: D
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Re: A parking lot contains ten cars. The average age of the cars is seven [#permalink]
Expert Reply
It's a weighted average problem so you can also use a number line:

--6--7-----------------C---

The ratio of the distances to the middle must be 1 to 9, since that's the ratio of the numbers of cars in each group, and since the smaller distance is 1, the larger distance is 9, and C = 7+9 = 16.

Of course with a problem set up in such a straightforward way, you don't need to use a weighted average method to solve - the methods posted above are just as easy.
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Re: A parking lot contains ten cars. The average age of the cars is seven [#permalink]
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