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Bunuel
A player throws a fair six-sided die. If a prime number is obtained, he wins an amount equal to the number rolled times 100 dollars, but if a prime number is not obtained, he loses an amount equal to the number rolled times 100 dollars. What is the provability that after two throws the player wins 400 dollars?

A. 1/10
B. 1/12
C. 1/18
D. 1/24
E. 1/36


This is a PS Butler Question


2, 3, 5 - winning numbers that will give him $200, 300 and 500 respectively
1, 4, 6 - Losing numbers that will make him lose $100, 400, 600 respectively

To WIN overall $400, he either wins on each turn or wins on one and loses on another.

Wins on each turn - He must throw 2 twice to make $400. He can't make 400 in any other way.
Probability = 1/6 * 1/6 = 1/36

Wins on one and loses on another - He must throw a 5 and a 1 to make $400.
Probability = 1/6 * 1/6 * 2 = 1/18

Overall probability = 1/12

Answer (B)
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